Answer:
a= 40-3b-c/5
a=-10+3b-2c
a=50+2b-3c/14
Step-by-step explanation:
5a+3b+c-(3b+c)=40-(3b+c)
5a=40-3b-c
5a/5=40/5-3b/5-c/5
a= 40-3b-c/5
a-3b+2c-(3b+2c)=-10-(-3b+2c)
a=-10+3b-2c
14a-2b+3c-(-2b+3c)=50-(-2b+3c)
14a=50+2b-3c
14a/14=50/14+2b/14-3c/14
a=50+2b-3c/14
The denominator can be 3 if the numerator is 1
Answer:
ok so. wheres the question
Answer:
Step-by-step explanation:
= 4.629 × 10•10•10•10
Answer:
The team has 92 wins and 38 losses.
Step-by-step explanation:
In a season 130 games are played by a baseball team.
Let us assume that the team wins x games and losses y games.
Therefore, we can write, x + y=130....... (1)
It is given that if the team won sixteen more games twice as many games as it lost.
So, we can conclude that x =2y+16 ......(2)
Hence, solving equations (1) and (2) we get, (2y+16) + y =130
⇒ 3y = 114
⇒ y =38
And from equation (2), x = 2×38 + 16 = 92
Therefore, the team has 92 wins and 38 losses. (Answer)
