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tia_tia [17]
4 years ago
14

Two optically flat glass plates, 16.0 cm long, are in contact at one end and separated by 0.0200 mm at the other end. The space

between the plates is occupied by oil with index of refraction 1.45. The index of refraction of the glass plates is 1.55. The plates are illuminated at normal incidence with monochromatic light, and fringes are observed. If the dark fringes are spaced 2.00 mm apart, what is the wavelength of the monochromatic lig
Physics
1 answer:
tiny-mole [99]4 years ago
5 0

Answer:

The wavelength of monochromatic light is - <u>725nm</u>

Explanation:

Lets calculate -

<u>Given -</u> The dark fringes are  2.0mm wide and the glass plate is 16.0cm

 Thus , the number of fringes is - n=\frac{16cm}{0.2mm}

                                  Here , converting the units into metre

                                                 = \frac{16m}{0.2\times10^-^3m}

                                                   = 80

Now , the expression used here is - 2nt=m\pi

        Putting the given values,

                    2\times (1.45)\times(2.0\times10^-^3)=80\pi

                     \pi =\frac{2\times1.45\times2.0\times10^-^3}{80}

                     \pi =7.25\times10^-^7m

                      =725\times10^-^9m

                       =725nm

<u>Therefore , the answer is 725nm . </u>                            

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