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Whitepunk [10]
3 years ago
8

The cart is initially at rest. Force

Physics
1 answer:
Oliga [24]3 years ago
5 0

Answer:

v'=\dfrac{1}{2}v

Explanation:

Given that,

Initial speed of the cart, u = 0

Let F force is applied to the cart for time \Delta t after which the car has speed v. The force on an object is given by :

F = ma

m is the mass of the cart

We need to find the speed of second cart, if the same force is applied for the same time to a second cart with twice the mass. Force becomes,

F=\dfrac{mv'}{t}

v'=\dfrac{F t}{2m}

v'=\dfrac{1}{2}v

So, the speed of second cart is half of the initial speed of first cart. So, the correct option is (b).

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<h2>Answer :</h2>

□ The Final velocity of body = 45 m/s\sf{ }

<h2>Given :</h2>

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<h2>To Calculate :</h2>

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<h2>How To Calculate ?</h2>

<h3>❒ </h3>

Here in this question we are provided that a body is in rest so it's initial velocity will be 0 m/s (because from rest), Acceleration of body is 3 m/s², and Time taken is also given which is 15 sec.

<h3>❒</h3>

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