Answer:
The given equation obey the law of conservation of mass.
Explanation:
Chemical equation:
2LiOH + CO₂ → Li₂CO₃ + H₂O
There are equal number of atoms of oxygen, hydrogen and lithium on both side of equation so it obey the law of conservation of mass.
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
2LiOH + CO₂ → Li₂CO₃ + H₂O
2(6.941 + 16 + 1) + 12+32 6.941×2 + 12 + 3×16 + 18
47.882 + 44 13.882 +12+48 + 18
91.882 g 91.882 g
The mass of reactants and product are equal.
Answer: half life
Explanation: Radioactive decay follows first order kinetics and the time required for the decay of a radioactive material is calculated as follows:
t= time required
k= disintegration constant
x= amount of substance left after time t
a= initial amount of substance
when one half of the sample is decayed, one half of the sample remains and t can be represented as
at ,
and .
Assuming complete decomposition of both samples,
First compound:
; of the first compound would contain
Oxygen and mercury atoms seemingly exist in the first compound at a ratio; thus the empirical formula for this compound would be where the subscript "1" is omitted.
Similarly, for the second compound
; of the first compound would contain
and therefore the empirical formula
.
They can change properties completely
They can be separated
They form a new set of elements and compounds
<span>The elements become part of the original compounds</span>
Answer:
6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.
Explanation:
The order of the reaction is 2.
Integrated rate law for second order kinetic is:
Where, is the initial concentration = 1.50 mol/L
is the final concentration = 1/3 of initial concentration = = 0.5 mol/L
Rate constant, k = 0.2 L/mol*s
Applying in the above equation as:-
<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>