The correct option is C.
The pitch of a string refers to the quality of sound that is produced by the string when it vibrates. There are three basic factors that affect the quality of pitch of a string, these are: the tension, the thickness of the string and the length of the string. The higher the thickness of the string, the lower the pitch of the string, thus, increasing the thickness of the string will lower the pitch.
We are given with
V = <span>2.394 x 102 mL
P = </span><span>7.20 x 102 mm of Hg
T = </span><span>78 oC
We are asked to determine the mass of the sample in milligrams
Using the ideal gas law
n = PV / RT
n = </span>7.20 x 102 mm of Hg (2.394 x 102 mL) / R (78 + 273)
Use the appropriate value for R or just convert the values to SI and use R = 8.314
Then, solve for the mass of the sample by using the MW Oxygen which is 16 g/mol
I searched for complete question (as your question is missing with structure) and found the structure of compound attached below.
Answer: The compound can
neither act as a Hydrogen Bond Donor
nor act as a Hydrogen Bond Acceptor.
Explanation: For two compounds to build Hydrogen Bond Interactions it is compulsory that they must contain Hydrogen atoms which are directly attached to most electronegative atoms like
Fluorine,
Oxygen and
Nitrogen.
As the given compound is
2-Butene (a non polar hydrocarbon), it lacks partial positive Hydrogen (which can act as Hydrogen Bond Donor) and a most electronegative element (F, O or N) which can act as Hydrogen Bond Acceptor. Therefore, this compound will not generate any Hydrogen Bonding with water molecules and will remain immiscible in it.