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Levart [38]
1 year ago
5

A molecule has an empirical formula of ch, and its molar mass is known to be 26 g/mol. What is its molecular formula?.

Chemistry
1 answer:
Sonbull [250]1 year ago
7 0

A molecule has an empirical formula of ch, and its molar mass is known to be 26 g/mol and the  molecular formula is C₂H₂ ethyne

Molecular formula of compound is (CH)n and the given molar mass is 26g/mol

Molar mass of (CH)n, C=12=n(12+1)=13n

So 13n and n=2

=13×2=26 and given molar mass is also 26g/mol

So here two carbon and two hydrogen so molecular formula is C₂H₂ and name is ethyne

Know more about molecular formula

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Which of the following species has
Kisachek [45]

Answer:

see explanation...

Explanation:

                               Mg⁺²-24                     Co⁺³-60                     Clˉ-35    

Protons (p⁺)                12                                 27                             17              

Neutrons (n⁰)             12                                 33                             18              

Electrons (eˉ)             10                                 24                             18              

                                  (c)                                 (b)                            (a)

                         12/2 : 12/2 : 10/2      27/3 : 33/3 : 24/3        #n⁰ = 18

                             6    :    6   :    5          9  :   11  :   8             #eˉ = 18

7 0
3 years ago
if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr
nignag [31]
Considering ideal gas:
PV= RTn

T= 25.2°C = 298.2 K

P1= 637 torr = 0.8382 atm

V1= 536 mL = 0.536 L

:. R=0.082 atm.L/K.mol

:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
((0.082 atmL/Kmol) x (298.2K))

:. n= O.0184 mol

Then,
P2= 712 torr = 0.936842 atm

V2 = RTn/P2 = [(0.082atmL/
Kmol) x (298.2K) x (0.0184mol) ]/(0.936842atm)

:.V2 = 0.4796 L
OR
V2 = 479.6 ml

6 0
3 years ago
When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
2 years ago
Nucleic acids are chains of 5-carbon sugars linked by ____ bonds with an organic base protruding from each sugar.
Mekhanik [1.2K]
<span>B) phosphodiester </span> is the correct answer
3 0
3 years ago
Convert 59,800 cg/L to g/mL
alexgriva [62]
To convert the given value to the desired one, use the proper unit conversions and dimensional analysis. Use the following conversion for the first set.

    1 g = 100 cg
    1 L = 1000 mL

Using the concept presented above,
         
            V = (59800 cg/L)(1 g/100 cg)1 L/1000 mL)
            V = 0.598 g/mL
6 0
3 years ago
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