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Vlada [557]
3 years ago
10

Complete combustion of 1.0 metric ton of coal (assuming pure carbon) to gaseous carbon dioxide releases 3.3 x 1010 j of heat. co

nvert this energy to kilocalories
Physics
1 answer:
netineya [11]3 years ago
6 0
Keeping in mind that the conversion between calories and Joules is
1 cal = 4.186 J
we can write the conversion factor using the kilocalories:
1 kcal = 4186 J

The energy released in our problem is
E=3.3 \cdot 10^{10} J 
so we can set a simple proportion to find its equivalent in kcal:
1 kcal: 4186 J = x: 3.3 \cdot 10^{10} J
from which we find:
x= \frac{3.3 \cdot 10^{10} J \cdot 1 kcal}{4186 J} =7.88 \cdot 10^6 kcal
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Acceleration = ( final velocity - intial velocity ) / time

= (60-0)m/s / 3s
= 20 m/s2
the answer is a
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4 years ago
Write the formulas of three important acids and three important bases. Describe their uses.
algol [13]

Explanation:

Acids HCl HNO3 H2SO4

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3 years ago
We can expect the force of friction to be greater for an object moving on a surface if the surfaces in contact are
nikitadnepr [17]

Answer:

c

Explanation:

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8 0
2 years ago
A man of mass m 1 5 70.0 kg is skating at v1 5 8.00 m/s behind his wife of mass m 2 5 50.0 kg, who is skating at v2 5 4.00 m/s.
ehidna [41]

Answer:

A. Kindly find attached free body diagram for your reference (smiles I guess I will make a terrible artist)

B. The collision is inelastic because both the husband and the wife moved together with same velocity as he grabs her on the waist

C. The general equation for conservation of momentum in terms of m 1, v 1, m 2, v 2, and final velocity vf

Say mass of husband is m1

Mass of the wife is m2

Velocity of the husband is v1

Velocity of the wife is v2

According to the conservation of momentum principle momentum before impact m1v1+m2v2 =momentum after impact Common velocity after impact (m1+m2)vf

The momentum equation is

m1v1+m2v2= (m1+m2)vf

D. To solve for vf we need to make it subject of formula

vf= {(m1v1) +(m2v2)}/(m1+m2)

E. Substituting our given data

vf=

{(1570*58)+(2550*54)}/(1570+2558)

vf=91060+137700/4120

vf=228760/4120

vf=55.52m/s

Their speed after collision is 55.52m/s

7 0
3 years ago
A mountain climber weighs 42.0 N. If he climbs a hill 100m high. Calculate the work done in joules​
quester [9]

Answer:

The answer is 4200 J.

Explanation:

The formula of work done is, W = F×D where F is the force of an object and D is the distance. Then you just substitute the values into the equation :

W = F×D

F = 42N

D = 100m

W = 42 × 100

= 4200 J

5 0
3 years ago
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