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Vlada [557]
3 years ago
10

Complete combustion of 1.0 metric ton of coal (assuming pure carbon) to gaseous carbon dioxide releases 3.3 x 1010 j of heat. co

nvert this energy to kilocalories
Physics
1 answer:
netineya [11]3 years ago
6 0
Keeping in mind that the conversion between calories and Joules is
1 cal = 4.186 J
we can write the conversion factor using the kilocalories:
1 kcal = 4186 J

The energy released in our problem is
E=3.3 \cdot 10^{10} J 
so we can set a simple proportion to find its equivalent in kcal:
1 kcal: 4186 J = x: 3.3 \cdot 10^{10} J
from which we find:
x= \frac{3.3 \cdot 10^{10} J \cdot 1 kcal}{4186 J} =7.88 \cdot 10^6 kcal
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stiks02 [169]

Answer:

b and c are the answers

A is an opinion, D is a superstitious belief because they haven’t found Jesus obviously

7 0
3 years ago
A speedboat initially at rest accelerates at 4.0 m/s (squared) for 7.0 s. How far does the speedboat move in 7.0 s?
Ulleksa [173]
I think is 3 becuase when he star at 4
4 0
3 years ago
A 2100-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 5.00 m before coming into contact w
aliya0001 [1]

Answer:

   f = 878,080 N

Explanation:

mass of pile driver (m) = 2100 kg

distance of pile driver to steel beam (s) = 5 m

depth of steel driven (d) = 12 cm = 0.12 m

acceleration due to gravity (g0 = 9.8 m/s^{2}

calculate the average force exerted on the pile driver by the beam.

  • from work done = force x distance
  • work done = change in potential energy of the pile driver
  • equating the two equations above we have

               force x distance = m x g x (s - d)

              f x 0.12 = 2100 x 9.8 x (5- (-0.12))

              d = - 0.12 because the steel beam went down at we are taking its  

              initial position to be an origin point which is 0

              f = ( 2100 x 9.8 x (5- (-0.12)) ) ÷ 0.12

                   f = 878,080 N

4 0
3 years ago
In a ballistics test, a 52g bullet hits a sand bag and stops after moving 1.34 m. If the initial bullat
olya-2409 [2.1K]

Answer:

Friction force on the bullet is 58.7 N opposite to its velocity

Explanation:

As we know that initial speed of the bullet is 55 m/s

after travelling into the sand bag by distance d = 1.34 m it comes to rest

so final speed

v_f = 0

now we can use kinematics top find the acceleration of the bullet

v_f^2 - v_i^2 = 2 a d

so we have

0 - 55^2 = 2(a)(1.34)

a = -1128.7 m/s^2

now by Newton's II law we know that

F = ma

so we have

F = (0.052)(-1128.7)

F = -58.7 N

8 0
3 years ago
After traveling for 6.0 seconds, a runner reaches 10m/s. What is the runner's acceleration?
luda_lava [24]

After traveling for 6.0 seconds, a runner reaches 10m/s. What is the runner's acceleration? Answer: 1.67 m/s2

4 0
3 years ago
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