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strojnjashka [21]
3 years ago
12

Does anyone like this?https://www.linkpicture.com/view.php?img=LPic6041468e32e151676981114

Physics
2 answers:
Bingel [31]3 years ago
7 0
Oh well it’s not that bad but I would to make the back part a little bit more out because it likes too in but I would say it’s good
Galina-37 [17]3 years ago
3 0

Answer:

taco bell

Explanation:

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Define refraction of light​
Elza [17]

Answer:

Refraction is the slowing down of light waves as they pass into a different medium and speeding as they pass out.

hope it helps. plz mark me as brainliest.

6 0
3 years ago
Neglecting air resistance, which of the following statements is true regarding an object in freefall?Lector inmersivo A. An obje
Dafna1 [17]

Answer:

E. An object’s velocity changes at a constant rate, and its acceleration remains constant.

Explanation:

When an object is in freefall, it implies that the object is falling freely under gravity. If it falls towards the earth surface, the fall is in the direction of the Earth's gravitational force.

At the point of release of the object, its initial velocity is zero because it is at rest. But when released, its velocity increases at a constant rate until it is acted upon by an external force. But its acceleration remains constant, acceleration due to gravity.

3 0
4 years ago
an object is placed in front of a curved mirror as shown. which of the labeled positions is the current position of the image
alexandr402 [8]

Answer:A

Explanation:

The image is formed behind the mirror.

4 0
3 years ago
Read 2 more answers
A 54 kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 1.3 m/s. The acceleration of
Marizza181 [45]

Answer:

h_{B} = 5.012\, m

Explanation:

It is assumed that pole vaulter began running at a height of zero. The physical model is formed after the Principle of Energy Conservation:

K_{A} = K_{B} + U_{B}

\frac{1}{2} \cdot m \cdot v_{A}^{2} = \frac{1}{2} \cdot m \cdot v_{B}^{2} + m \cdot g \cdot h_{B}

The previous expression is simplified and required height is found:

h_{B} = \frac{1}{2\cdot g} \cdot (v_{A}^{2}-v_{B}^{2})

h_{B} = \frac{1}{2 \cdot (9.807\, \frac{m}{s^{2}} )} \cdot [(10\, \frac{m}{s} )^{2}-(1.3\, \frac{m}{s} )^{2}]

h_{B} = 5.012\, m

5 0
4 years ago
How much did the temperature change between 10 a.m. and 1 p.m.?
yanalaym [24]

First take note that you're figuring 10am and 1pm. Their temperatures are 77 degrees and 83 degrees

To solve subtract 83-77=6

So it rose 6 degrees.

4 0
4 years ago
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