When you’re driving on the freeway it’s necessary to keep your foot on the accelerator to keep the car moving at a constant speed. In this situation the net force on the car is zero.
The rate of change of the velocity of a particle with respect to time is called its acceleration. If the velocity of the particle changes at a constant rate, then this rate is called the constant acceleration.
Since we are using metres and seconds as our basic units, we will measure acceleration in metres per second per second. This will be abbreviated as m/s². It is also commonly abbreviated as ms⁻².
For example, if the velocity of a particle moving in a straight line changes uniformly (at a constant rate of change) from 2 m/s to 5 m/s over one second, then its constant acceleration is 3 m/s².
Zero acceleration means constant velocity. Also to be noticed is that the definition of acceleration does not involve any information about forces. Acceleration is a kinematic quantity. Irrespective of what forces are acting, if the velocity is constant, the acceleration is zero.
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Answer:
Say you are holding a thread to the end of which is tied a stone. Now when you start whirling it around you will notice that two forces have to be applied simultaneously. One which pulls the thread inwards and the other which throws it sideways or tangentially.
Both these forces will generate their respective accelerations.
The one pointed inwards will generate centripetal or radial acceleration.
The one pointing sideways will generate tangential acceleratio
Explanation:
A major difference between tangential acceleration and centripetal acceleration is their direction
Centripetal means “center seeking”. Centripetal acceleration is always directed inward.
Tangential acceleration is always directed tangent to the circle.
Tangential acceleration results from the change in magnitude of the tangential velocity of an
object. An object can move in a circle and not have any tangential acceleration. No tangential
acceleration simply means the angular acceleration of the object is zero and the object is moving
with a constant angular velocity
Answer:
D. 12.4 m
Explanation:
Given that,
The initial velocity of the ball, u = 18 m/s
The angle at which the ball is projected, θ = 60°
The maximum height of the ball is given by the formula
h = u² sin²θ/2g m
Where,
g - acceleration due to gravity. (9.8 m/s)
Substituting the values in the above equation
h = 18² · sin²60 / 2 x 9.8
= 18² x 0.75 / 2 x 9.8
= 12.4 m
Hence, the maximum height of the ball attained, h = 12.4 m
Answer:
79.2 m/s
Explanation:
θ = angle at which projectile is launched = 29.7 deg
a = initial speed of launch = 130 m/s
Consider the motion along the vertical direction
v₀ = initial velocity along the vertical direction = a Sinθ = 130 Sin29.7 = 64.4 m/s
y = vertical displacement = - 108 m
a = acceleration = - 9.8 m/s²
v = final speed as it strikes the ground
Using the kinematics equation
v² = v₀² + 2 a y
v² = 64.4² + 2 (-9.8) (-108)
v = 79.2 m/s