What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A
1 answer:
Answer:
15.34 kVA
Explanation:
A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.
The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.
Hence Power (P) =√3 × voltage (V) × current (I)
P = √3 × V × I
Given that voltage (V) = 460 V, current (I) = 17 A. Hence:
P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA
But 1000 VA = 1 kVA. Hence:
You might be interested in
Taking into account the definition of density, the volume of the metal block is 3 m³.
<h3>What is density</h3>Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
<h3>Volume of the metal block</h3>In this case, you know that:
- Density= 5000
- Mass= 15000 kg
- Volume= ?
Replacing in the definition of density:
Solving:
volume×5000 = 15000 kg
volume=
<u><em>volume= 3 m³</em></u>
In summary, the volume of the metal block is 3 m³.
Learn more about density:
#SPJ12