What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A
1 answer:
Answer:
15.34 kVA
Explanation:
A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.
The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.
Hence Power (P) =√3 × voltage (V) × current (I)
P = √3 × V × I
Given that voltage (V) = 460 V, current (I) = 17 A. Hence:
P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA
But 1000 VA = 1 kVA. Hence:
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a) The force that must be applied is 73.5 N
b) The actual efficiency is 82 %
Explanation:
a)
Since the jack is 100% efficient, all the input work is converted into output work. So we can write:
where:
is the input force applied on the jack
is the arm of the input force
is the output force applied on the jack
is the arm of the output force
Here we have:
is the output force (half the weight of the car)
is the arm of the input force
is the arm of the output force
Solving for , we find the force that must be applied in input to lift the car:
b)
The efficiency of the jack is given by the ratio between the output work and the input work:
where we have:
is the output force (half the weight of the car)
is the arm of the input force
is the arm of the output force
Here we are told that the input force this time is
Substituting into the equation, we find the new efficiency of the jack:
Which means an efficiency of 82%.
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