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romanna [79]
3 years ago
10

What is the kinetic energy of a 130 kg football lineman running at 6m/s?

Physics
1 answer:
Fittoniya [83]3 years ago
3 0
Kinetic energy= 1/2mv^2
=1/2*130*6^2
=2340J
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Select the statements that are TRUE. Electrophilic aromatic substitution reactions have energies of activation that are very low
NikAS [45]

Answer:

Addition reactions with benzenes lead to the loss of aromaticity.

Benzene and its derivatives undergo a type of substitution reaction in which a hydrogen atom is replaced by a substituent, but the stable aromatic benzene ring is regenerated at the end of the mechanism.

Benzene and its derivatives tend to undergo electrophilic aromatic substitution reactions.

Explanation:

5 0
3 years ago
Calculate the force exerted on this test dummy with a mass of 75 kg hits an air bag accelerating at 12 m/s2.
maksim [4K]

Answer: 900

Explanation: Force equals mass x acceleration F=M×A

3 0
3 years ago
An airplane flies between two points on the ground that are 500 km apart. The destination is directly north of the origination o
Ann [662]

Answer:

   θ = 4.78º

with respect to the vertical or 4.78 to the east - north

Explanation:

This is a velocity compound exercise since it is a vector quantity.

The plane takes a direction, the air blows to the west and the result must be to the north, let's use the Pythagorean theorem to find the speed

                  v_fly² = v_nort² + v_air²

                  v_nort² = v_fly² + - v_air²

Let's use trigonometry to find the direction of the plane

        sin θ = v_air / v_fly

        θ = sin⁻¹ (v_air / v_fly)

         

let's calculate

        θ = sin⁻¹ (10/120)

         θ = 4.78º

with respect to the vertical or 4.78 to the north-east

5 0
3 years ago
What is the altitude of the Sun at noon on December 22, as seen from a place on the Tropic of Cancer?
scZoUnD [109]

Answer:

108.217 °

Explanation:

Day of year = 356 = d (Considering year of 365 days)

Latitude of Tropic of Cancer = 23.5 °N

Declination angle

δ = 23.45×sin[(360/365)(d+284)]

⇒δ = 23.45×sin[(360/365)(356+284)]

⇒δ = 5.2832 °

Altitude angle at solar noon

90+Latitude-Declination angle

= 90+23.5-5.2832

= 108.217 °

∴ Altitude angle of the Sun as seen from the tropic of cancer on December 22 is 108.217 °

4 0
3 years ago
A soccer ball is released from rest at the top of a grassy incline. After 6.2 seconds, the ball travels 47 meters. One second la
alexandr1967 [171]

Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

Explanation:

(a)

We will use the second equation of motion here:

s = v_it+\frac{1}{2}at^2

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

t = time taken = 6.2 s

a = acceleration = ?

Therefore,

47\ m = (0\ m/s)(6.2\ s)+\frac{1}{2}a(6.2\ s)^2\\\\a = \frac{2(47\ m)}{(6.2\ s)^2}

<u>a = 2.44 m/s²</u>

<u></u>

(b)

Now, we will again use the second equation of motion for the complete length of the inclined plane:

s = v_it+\frac{1}{2}at^2

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\

<u>s = 63.24 m</u>

6 0
3 years ago
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