The greatest possible number of club members is 7
<em><u>Solution:</u></em>
Given that, local readers’ club has a set of 49 hardback books and a set of 21 paperbacks
Each set can be divided equally among the club members
To find the greatest possible number of club members, we have to find the greatest common factor of 49 and 21
The greatest number that is a factor of two (or more) other numbers.
When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.
<em><u>Greatest common factor of 49 and 21:</u></em>
The factors of 21 are: 1, 3, 7, 21
The factors of 49 are: 1, 7, 49
Then the greatest common factor is 7
Thus, the greatest possible number of club members is 7
Answer:
The answer is B I think
Step-by-step explanation:
They are talking about how they are convinced about the people who speed
The third choice is appropriate.
an = 5 - 3(n - 1); all integers n ≥ 1
_____
This equation follows the form for the general term of an arithmetic sequence.
an = a1 + d(n - 1)
where a1 is the first term (corresponding to n=1), and d is the common difference. From the problem statement, a1 = 5 and d = 2 - 5 = -3.
Answer:
Convert to a decimal by dividing the numerator by the denominator.
4.43349753 just easy
good morning,
Answer:
10×(1-0.2ⁿ)
Step-by-step explanation:
1.6/8=0.2
0.32/1.6=0.2
0.064/0.32=0.2
let S represent the sum of n term then S=8×[(1-0.2ⁿ)/(1-0.2)] = 10×(1-0.2ⁿ).
:)