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Westkost [7]
3 years ago
9

Suppose you have an object tied to a rope and are rotating it over your head in uniform circular motion. What would have to do t

o the rope length in order to cut the centripetal force in half
Physics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

We must duplicate the length of the rope (R'=2R) to get

F'=\frac{1}{2}F

Explanation:

The equation of the centripetal force is given by:

F_{c}=ma_{c}

F_{c}=m\frac{v^{2}}{R}

Where:

R is the length of the rope

m is the mass of the object

v is the speed of the object

If we want to reduce the centripetal force in half, we can duplicate the length of the rope (R'=2R), which means:

F'_{c}=m\frac{v^{2}}{R'}

F'_{c}=m\frac{v^{2}}{2R}

F'_{c}=\frac{1}{2}F_{c}

I hope it helps you!

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