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RSB [31]
3 years ago
5

Match the following properties to the type of wave.

Physics
2 answers:
Harman [31]3 years ago
7 0

Explanation:

1 . 3

2. 1

3. 2

I hope it is helpful to you.

Reil [10]3 years ago
6 0

Answer:

hi there

Explanation:

1 - III

2- 1

3-1

HOPE IT HELP YOU

PLz mark me as a BRAINLIST

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Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 170 V. An electron ent
notsponge [240]

Answer:

Explanation:

Electric field between plates

V / d

= 170 / ( 2 x 10⁻² )

= 8500 N/C

Force on electron in this field

= 8500 x 1.6 x 10⁻¹⁹

= 13600 x 10⁻¹⁹ N

Acceleration

= 13600 x 10⁻¹⁹ / 9.1 x 10⁻³¹

a = 1494.5 x 10¹² m /s²

s = .1 x 10⁻² m

v² = u² + 2as

=  (2.9x 10⁵)²+ 2 x 1494.5 x 10¹² x .1 x 10⁻²

= 8.41 x 10¹⁰ + 299 x 10¹⁰

= (8.41 + 299 ) x 10¹⁰

v = 17.53  x 10⁵ m /s

8 0
3 years ago
Which statement best explains the movement of electric current from the clouds to the ground during a lightning storm? .
olga2289 [7]
"The <span>ground is positively charged and the clouds are negatively charged " is the statement among the statements given in the question that </span><span>best explains the movement of electric current from the clouds to the ground during a lightning storm. The correct option among all the options that are given in the question is the third option or option "C". </span>
3 0
3 years ago
Read 2 more answers
A swing has a period of 10 seconds. What is its frequency ?
kow [346]

Frequency = 1 / (period)

Frequency = 1 / (10 seconds) = (1/10) ( / second) = 0.1 per second = <em>0.1 Hz</em>.


4 0
3 years ago
Sound enters the ear, travels through the auditory canal, and reaches the eardrum. The auditory canal is approximately a tube op
Juliette [100K]

Answer:

The fundamental frequency of can is 2.7 kHz.                          

Explanation:

Given that,

A typical length for the auditory canal in an adult is about 3.1 cm, l = 3.1 cm

The speed of sound is, v = 336 m/s

We need to find the fundamental frequency of the canal. For a tube open at only one end, the fundamental frequency is given by :

f=\dfrac{v}{4l}\\\\f=\dfrac{336}{4\times 3.1\times 10^{-2}}\\\\f=2709.67\ Hz\\\\f=2.7\ kHz

So, the fundamental frequency of can is 2.7 kHz. Hence, this is the required solution.

7 0
3 years ago
At a certain point in space, there is a potential of 800 V relative to zero. What is the potential energy of the system when a +
sammy [17]

To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:

V = \frac{k_e q}{r}

k_e = Coulomb's constant

q = Charge

r = Radius

At the same time

U = \frac{k_e q_1q_2}{r}

The values of variables are the same, then if we replace in a single equation we have this expression,

U  = Vq

If we replace the values, we have finally that the charge is,

V = 800V

q = 1\mu C

U = (800V)(1*10^{-6}C)

U = 8*10^{-4}J

Therefore the potential energy of the system is 8*10^{-4} J

7 0
3 years ago
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