Answer:
[ S2- ] = 4.0 E-47 M
Explanation:
- PbS(s) → Pb2+ + S2-
- HgS(s) → Hg2+ + S2-
∴ Ksp PbS = 3.4 E-28 = [Pb2+]*[S2-]
∴ [Pb2+] = 0.181 M
∴ Ksp HgS = 4.0 E-53 = [Hg2+]*[S2-]
∴ [Hg2+] = 0.174 M
∴ Ksp PbS > Ksp HgS ⇒ precipitate first Hg2+:
∴ [ Hg2+ ] = 1.0 E-6 M
⇒ [S2-] = 4.0 E-53 / 1.0 E-6 = 4.0 E-47 M
Answer:
It is Likely to Be Sodium (Na) coz as You Down The group the reactivity increase
Answer:
hello some part of your question is missing below is the missing part
1. Mass of water in the boiler 336.6g 2. Mass of wax burn 0.289g 3. Increased in the temperature 6.6 C
and change to Joules and to kilojoules
answer : 9.295 kJ
Explanation:
Calculate how much energy was released by the combustion of the wax
ΔT = 6.6°C
<em>Note :The energy released by the combustion of wax is absorbed by the water </em>
heat = mass * specific heat capacity * ΔT
= 336.6 * 1 * 6.6 = 221.56 cal
convert; 221.56 cal to J
= 221.56 * 4.184 = 9295.0 J
<em>hence the energy released by the combustion of the wax = 9.295 kJ</em>
