The symbol of the radioactive nuclide, given the data is ⁴⁰₁₉K
<h3>Data obtained from the question</h3>
- Atomic number = 19
- Mass number = 40
- Symbol of nuclide =?
<h3>How to determine the nuclide</h3>
From the question given above, the atomic number of the nuclide is 19.
Comparing the atomic number (i.e 19) of the nuclide with those in the periodic table, the nuclide is potassium with a symbol of K
<h3>How to determine the symbol of the nuclide</h3>
- Atomic number (Z) = 19
- Mass number (A) = 40
- Name of nuclide = Potassium (K)
- Symbol of nuclide =?
The symbol of a nuclide is given as ᴬ₂X
Where
- A is the mass number
- Z is the atomic number
- X is the symbol of the element
Thus,
ᴬ₂X => ⁴⁰₁₉K
Therefore, the symbol of the nuclide is ⁴⁰₁₉K
Learn more about composition of atoms:
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Answer: 500
Explanation: Since there are fifty tens, you must multiply 50 by 10, in which will get you 500 as your final answer.
Answer:
Benzaldehyde is less electrophilic than acetaldehyde
Explanation:
Electrophilicity of carbonyl carbon depends on it's positive charge density.
In benzaldehyde, phenyl group can act as an electron donating group towards carbonyl group due to it's electron donating resonating effect.
In acetaldehyde, methyl group can act as an electron donating group towards carbonyl group due to it's electron donating inductive effect.
We know that resonating effect are more stronger than inductive effect.
Henece, it is expected that positive charge density on carbonyl carbon is much lower in benzaldehyde than acetaldehyde.
So, benzaldehyde is less electrophilic than acetaldehyde.
Resonating effect of phenyl group has been shown below.
Exothermic. Exothermic exo meaning out, release heat while endothermic, endo as in in, take in heat.
Answer:
it's SN1 reaction,
it's takin double step to complete,first formation of carbocation and then attack of reagents,so it's SN1!
