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brilliants [131]
2 years ago
15

Which Group is in the leftmost column on the periodic table?

Chemistry
2 answers:
Naddika [18.5K]2 years ago
5 0

Answer:

C. Alkali metals

Explanation:

When looking at the left side of the periodic table, you'll find the alkali metals, which is a subgroup of Metals

svp [43]2 years ago
4 0
Alkali metals. Hope this helps
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A sample of hydrogen gas will behave most like an ideal gas under the conditions of
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Answer:

The Answer is gonna be C) high pressure and low temperature

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Which type of radioactive emission has a positive charge and weak penetrating power?
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3 years ago
Does water added to a flask containing chlorine gas and solid sodium react in the chemical reaction to make sodium chloride
Jet001 [13]

Answer:

Explanation:

Chemically, we can have a reaction between chlorine gas and solid sodium

This reaction is actually explosive and would produce fine powder of sodium chloride

We have the reaction as follows:

2Na_{(s)}+Cl_{2(g)}\rightarrow2NaCl_{(s)}

Essentally, what we can deduce from here is that we do not need to add water to the flask. Except for the reason that we would want the sodium chloride solid in the solution form, there is absolutely no reason to add water to the flask as the reaction would proceed normally

5 0
1 year ago
A 5.50 gram sample of C2H6 gas has a volume of 2.50 L. If the sample is at 41.20C, what will it’s pressure be?
vovangra [49]
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8 0
3 years ago
Concerning Boyle's Law, if you had a gas at a pressure of 101 kPa and decreased the volume of the container holding the gas to o
Viefleur [7K]

Answer:

P_2=404 kPa

Explanation:

Hello,

In this case, the Boyle's is mathematically defined via:

P_1V_1=P_2V_2

Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:

V_2=\frac{1}{4} V_1

We can compute the new pressure:

P_2=\frac{P_1V_1}{V_2} =\frac{P_1V_1}{\frac{1}{4} V_1} =\frac{101kPa*V_1}{\frac{1}{4} V_1} \\\\P_2=4*101kPa\\\\\\P_2=404 kPa

Which means the pressure is increased by a factor of four.

Regards.

7 0
3 years ago
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