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3 years ago

Consider the solution containing 0.181 M lead ions and 0.174

Chemistry

1 answer:

Luba_88 [7]3 years ago

8 0

Answer:

[ S2- ] = 4.0 E-47 M

Explanation:

PbS(s) → Pb2+ + S2-
HgS(s) → Hg2+ + S2-

∴ Ksp PbS = 3.4 E-28 = [Pb2+]*[S2-]

∴ [Pb2+] = 0.181 M

∴ Ksp HgS = 4.0 E-53 = [Hg2+]*[S2-]

∴ [Hg2+] = 0.174 M

∴ Ksp PbS > Ksp HgS ⇒ precipitate first Hg2+:

∴ [ Hg2+ ] = 1.0 E-6 M

⇒ [S2-] = 4.0 E-53 / 1.0 E-6 = 4.0 E-47 M

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Number of molecules for $55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$

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learn more:

Dalton model of the atom brainly.com/question/1979129

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