3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.
Explanation:
data given:
H30+= 1.40 X 10^-4 M\
Henderson Hasslebalch equation to calculate pH=
pH = -log10(H30+)
putting the values in the equation:
pH = -log 10(1.40 X 10^-4 M)
pH = 3.85
pH + pOH =14
pOH = 14 - 3.85
pOH = 10.15
The OH- concentration from the pOH by the equation:
pOH = -log10[OH-]
10.5= -log10[OH-]
[OH-] = 10^-10.5
[OH-] = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.
If we have in mind the following procedure:
BACo3(s) + H +1 -> Ba +2 + HCO3 -1
CO3 - 2 + H+1 -> HCO3 -1
As nitric acid is added then {CO3 -2 } decreases meaning that more BaCo3 can dissolve. The graph you need to use is the one that the curve goes down and closer to solubility and goes up on conc.
Answer:
Saturn
Explanation:
One whole orbit is a year on earth. Well it takes Saturn 10,759 days to make one whole orbit. It takes Jupiter 4,333 days to make a whole orbit.
Answer:
The answer is 0.01 M
Explanation:
The problem is solved by applying the expression for ionic product of water as follows:
Kw = [H₃O⁺] [OH⁻]
Where Kw is the ionic product of water and it is 1.10⁻¹⁴ M at⁴ 25ºC. As [OH⁻]= 1.10⁻¹² M, [H₃O⁺] will be:
[H₃O⁺]= Kw/ [OH⁻]= 1.10⁻¹⁴M/1.10⁻¹²M= 0.01 M
Answer:THIS IS NOT THE ANSWER
is this for the chemistry A final 10th grade for connexus (unit7 lesson 2)?
Explanation:
