Question

How do I find the answer for question 3 and 4?

Answer 1

Q3) 1.5 mL from the 1.00 M HCl stock solution

Q4) 0.15 mL from the 1.00 × 10⁻¹ M NaOH stock solution

Explanation:

Q3) Determine the amount of 1.00 M HCl stock solution needed to form 100 mL of 1.50 × 10⁻² M HCl solution.

Q4)  Determine the amount of 1.00 × 10⁻¹ M stock NaOH solution needed to form 100 mL of 1.50 × 10⁻² M NaOH solution.

To solve both of the questions we use the following formula:

initial concentration × initial volume =  final concentration × final volume

For Q3 we have:

initial concentration = 1.00 M HCl

initial volume = ?

final concentration =  1.50 × 10⁻² M HCl

final volume = 100 mL

1.00 × initial volume = 1.50 × 10⁻² × 100

initial volume = ( 1.50 × 10⁻² × 100) / 1.00

initial volume = 1.5 mL from the 1.00 M HCl stock solution

For Q4 we have:

initial concentration = 1.00 × 10⁻¹ M NaOH

initial volume = ?

final concentration =  1.50 × 10⁻² M NaOH

final volume = 100 mL

1.00 × 10⁻¹ × initial volume = 1.50 × 10⁻² × 100

initial volume = ( 1.50 × 10⁻² × 100) / 1.00 × 10⁻¹

initial volume = 0.15 mL from the 1.00 × 10⁻¹ M NaOH stock solution

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