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gavmur [86]
4 years ago
5

What is the percentage by mass of nacl in a saturated solution of sodium chloride at 50c

Chemistry
1 answer:
Flura [38]4 years ago
7 0
<span>27% thats it ^ u ^ yeah</span>
You might be interested in
1. How many moles are in 15.5 g of SO2
Maurinko [17]

1. The number of mole in 15.5 g of SO₂ is 0.242 mole

2. The mass of 1.50 mole of C₃H₈ is 66 g

3. The number of mole of NH₃ that contains 1.5×10²³ molecules is 0.249 moles

4. The mass of NaCl that contains 2.5×10²⁵ formula units is 2429.4 g

5. The number of molecules present in 3.6 moles of CO₂ is 2.167×10²⁴ molecules

<h3>1. How to determine the mole of SO₂</h3>
  • Mass of SO₂ = 15.5 g
  • Molar mass of SO₂ = 32 + (2×16) = 64 g/mol
  • Mole of SO₂ =?

Mole = mass / molar mass

Mole of SO₂ = 15.5 / 64

Mole of SO₂ = 0.242 mole

<h3>2. How to determine the mass of C₃H₈</h3>
  • Mole of C₃H₈ = 1.5 mole
  • Molar mass of C₃H₈ = 44 g/mol
  • Mass of C₃H₈ =?

Mass = mole × molar mass

Mass of C₃H₈ = 1.5 × 44

Mass of C₃H₈ = 66 g

<h3>3. How to determine the mole of NH₃ </h3>

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of NH₃

Therefore,

1.5×10²³ molecules = 1.5×10²³ / 6.02×10²³

1.5×10²³ molecules = 0.249 mole of NH₃

<h3>4. How to determine the mass of NaCl </h3>

6.02×10²³ units = 58.5 g of NaCl

Therefore,

2.5×10²⁵ units = (2.5×10²⁵ × 58.5) / 6.02×10²³

2.5×10²⁵ units = 2429.4 g of NaCl

<h3>5. How to determine the number of molecules </h3>

1 mole of CO₂ = 6.02×10²³ molecules

Therefore,

3.6 moles of CO₂ = 3.6 × 6.02×10²³

3.6 moles of CO₂ = 2.167×10²⁴ molecules

Learn more about Avogadro's number:

brainly.com/question/26141731

3 0
2 years ago
The equilibrium constant Kc for the reaction
PIT_PIT [208]

Answer:

[N2] = 0.3633M

[H2] = 1.090M

[NH3] = 0.2734M

Explanation:

Based on the reaction of the problem, Kc is defined as:

Kc = 0.159 = [NH3]² / [N2] [H2]³

<em>Where [] are the equilibrium concentrations.</em>

The initial concentrations of the reactants is:

N2 = 1.00mol / 2.00L = 0.500M

H2 = 3.00mol / 2.00L = 1.50M

When the equilibrium is reached, the concentrations are:

[N2] = 0.500M - X

[H2] = 1.50M - 3X

[NH3] = 2X

<em>Where X is reaction quotient</em>

Replacing in the Kc equation:

0.159 = [2X]² / [0.500 - X] [1.50 - 3X]³

0.159 = 4X² / 1.6875 - 13.5 X + 40.5 X² - 54 X³ + 27 X⁴

0.268313 - 2.1465 X + 6.4395 X² - 8.586 X³ + 4.293 X⁴ = 4X²

0.268313 - 2.1465 X + 2.4395 X² - 8.586 X³ + 4.293 X⁴ = 0

Solving for X:

X = 0.1367. Right solution.

X = 1.8286. False solution. Produce negative concentrations

Replacing:

[N2] = 0.500M - 0.1367M

[H2] = 1.50M - 3*0.1367M

[NH3] = 2*0.1367M

The equilibrium concentrations are:

<h3>[N2] = 0.3633M</h3><h3>[H2] = 1.090M</h3><h3>[NH3] = 0.2734M</h3>

3 0
3 years ago
Balance the half reaction, c5o5 2-(g) â co3 2-(aq), taking place in basic media. which answer below describes how many hydroxide
Ludmilka [50]

Answer is: 20 ions, left side.

Unbalanced half reaction: C₅O₅²⁻(g) → CO₃²⁻(aq).

1) There are 5 carbon atoms on the left side of half reaction and 1 carbon atom on right, so first add coefficient 5 in fron of carbon dioxide to balance carbon atoms: C₅O₅²⁻(g) → 5CO₃²⁻(aq).

2) Because there are more oxygen atoms on the right, add OH⁻ ions on the left side of half reaction and water on the right: OH⁻(aq) + C₅O₅²⁻(g) → 5CO₃²⁻(aq) + H₂O(l).

3) Balance oxygen (25 atoms on boths side) and hydrogen (20 atoms on both side of half reaction) atoms:

Balanced half reaction: 20OH⁻(aq) + C₅O₅²⁻(g) → 5CO₃²⁻(aq) + 10H₂O(l).

7 0
3 years ago
What chemical bonds stabilize the different structures in primary, secondary, tertiary and quaternary structures?.
Blababa [14]

Peptide bonds, hydrogen bonds, disulfide linkages, van der Waals, and electrostatic forces of attraction are the chemical bonds that stabilize the different structures in primary, secondary, tertiary, and quaternary structures.

The advanced structure of proteins gives rise to two kinds of major molecular shapes which are fibrous as well as globular structures. The main forces which are involved in stabilizing the secondary along with the tertiary structures of proteins include hydrogen bonds, disulfide type linkages, van der Waals attraction, and electrostatic forces of attraction.

The primary structure is generally determined by adjoining peptide bonds where the link is adjoining amino acids in sequential order. Tertiary structure is determined by the existence of disulfide bonds in between hydrophobic interactions as well as cysteine residues whereas the quaternary type structure is determined by multiple subunits of a protein that undergo various interactions.

Hydrogen bonds exist in a protein molecule as its large number can form between adjacent regions of the polypeptide chain in folded form and stabilize its three-dimensional kind of shape.

Learn to know more about levels of protein structure on

brainly.com/question/17338734

#SPJ4

4 0
1 year ago
Use the drop-down menu to complete the sentence.
Paha777 [63]

Answer:

It's called carbon dioxide.

Explanation:

CO_{2} consists of 1 carbon atom bonding with two oxygen atoms.

5 0
3 years ago
Read 2 more answers
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