Answer:
The rocket would be in the air for 8.125 seconds after launch.
Step-by-step explanation:
Given that the height of the rocket, h = 260t - 16
.
To determine how long the rocket would be in the air, differentiate h totally with respect to t.
So that, total derivative of h is given as;
= 
0 = 260 - 16 x 2t
= 260 - 32t
0 = 260 - 32t
32t = 260
t = 
= 8.125
t= 8.125 seconds
The rocket would be in the air for 8.125 seconds after launch.
Answer:
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Step-by-step explanation:
hey man. trust me. quack
Each side of a square is the same, so the area of a square is one side times another of the same length. In other words it's side x side or side2
This is where we get the term "square root".
s2 = 49
take the square root of each side
s = 7
So we have the equation:

So we first must multiply both sides by 4 in order to get rid of the
on the left side:

Then we need to subtract 15 on both sides in order to get the x term by itself on the left side:

And then to completely solve for x, we need to divide both sides by 4:
