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Soloha48 [4]
3 years ago
15

Air resistance allow objects to develop full acceleration due to gravity true or false

Physics
1 answer:
Aloiza [94]3 years ago
3 0
False. because the object cannot freefall due to resistance, so it cannot develop full acceleration.
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A ___ is the unit of measurement for force.
bogdanovich [222]

Answer:

Newton (N)

Explanation:

A newton is the unit of measurement for force

4 0
3 years ago
45. What is the wovelength of a 30. Hertz periodic
Leviafan [203]

The wavelength is 2m.

Hence, Option c) 2m is the correct answer

Given that;

Frequency; f = 30Hz

Speed; v = 60m/s

Wavelength; \lambda =\ ?

using the expression for the relations between wavelength, frequency and speed of wave:

\lambda = \frac{v}{f}

Where \lambda is wavelength, f is frequency and v is speed.

We substitute our given values into the equation

\lambda = \frac{60m/s}{30Hz}\\\\\lambda = \frac{60m/s}{30s^{-1}}\\\\\lambda = 2m

The wavelength is 2m.

Hence, Option c) 2m is the correct answer.

To learn more about wavelength, click here: brainly.com/question/1347107

4 0
2 years ago
I need help in this small question:
Natali5045456 [20]

Answer:

1) The energy released during nuclear fission or fusion, especially when used to generate electricity is called nuclear energy.

2) It is not renewable because it is an element that has no way whatsoever to regenerate or replicate itself, nor gets created by any natural terrestrial means, neither makes itself available by arriving from outer space (like sunlight). There is a limited amount of it available on the Earth, and every bit you use is a bit you’ll never have available again (as Uranium atoms get destroyed by the fission process).

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5 0
3 years ago
A steel bar of rectangular cross section (1.5 in. 2 3 .0 in.) carries a tensile load P (see fig- ure). The allowable stresses in
lukranit [14]

Explanation:

Value of the cross-sectional area is as follows.

        A = 1.5 \times 2.30

           = 3.45 in^{2}

The given data is as follows.

          Allowable stress = 14,500 psi

          Shear stress = 7100 psi

Now, we will calculate maximum load from allowable stress as follows.

           P_{max} = \sigma_{a}A

                       = 14500 \times 3.45

                       = 50025 lb

Now, maximum load from shear stress is as follows.

           P_{max} = 2 \times \tau_{a} \times A

                      = 2 \times 7100 \times 3.45

                      = 48990 lb

Hence, P_{max} will be calculated as follows.

       P_{max} = min((P_{max})_{\sigma}, (P_{max})_{\tau})

                  = 48990 lb

Thus, we can conclude that the maximum permissible load P_{max} is 48990 lb.

4 0
4 years ago
A biologist looking through a microscope sees a bacterium at r⃗ 1=2.2i^+3.7j^−1.2k^μm(1μm=10−6m). After 6.2 s , it's at r⃗ 2=4.6
stiv31 [10]

The Average velocity for the bacterium is 0.75 unit/sec.

<u>Explanation:</u>

The given values are in the vector form

Where,

dS = distance covered

dT = time interval

Now, to calculate distance covered, we have

|d S|=\sqrt{d S^{2}}

&

d S=r_{2}-r_{1}

d S=(4.6 i+1.9 k)-(2.2 i+3.7 j - 1.2 k)

d S=(4.6-2.2) i+(0-3.7) j+(1.9+1.2) k

d S=2.4 i-3.7 j+3.1 k

Now, putting these values in the standard formula to evaluate the average velocity, we get;

v_{a v g}=\frac{|\mathrm{d} S|}{d T}

v(a v g)=\frac{|\sqrt{\left\{\left(2.4^{2}\right)+\left(3.7^{2}\right)+\left(3.1^{2}\right)\right\}}|}{7.2}

As dT=7.2 sec

Now,

Solving the equation, we get;

v(a v g)=\frac{5.390732789}{7.2}

\begin{aligned}&v(a v g)=\frac{5.39}{7.2}\\&v(a v g)=0.748611111\\&v(a v g)=0.75 \text { units / sec }\end{aligned}

Hence, the average velocity for the bacterium is 0.75 unit/sec.

3 0
3 years ago
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