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Refer to the diagram shown below.
The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N
Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m
This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N
Answer: 4.04 N
'Traveling around a circular track' can be a description of constant
acceleration due only to changes in direction. But if it is, then the
progress around the circular track must be at constant speed.
The correct answer for that question would be. A