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BabaBlast [244]
3 years ago
14

Explain how Copernicus concluded that stars were farther away than planets. Draw a diagram showing how this principle applies to

another example.
Physics
1 answer:
Rainbow [258]3 years ago
8 0
<span>Copernicus decided this with more of an educated guess than anything. For example is when your standing right next to a plane it's huge Right? Well when it's flying it looks really small. He used the same reasoning for stars. Since it looks small it must be farther away.</span>
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ASAP! please help me MCQ. Thank you
Dmitriy789 [7]

Answer:13m

Explanation:

6 0
2 years ago
Read 2 more answers
A 20.00 kg lead sphere is hanging from a hook by a thin, massless wire 2.80 m long and is free to swing in a complete circle. Tr
Tema [17]

The minimum initial speed of the dart so that the combination makes a complete circular loop after the collision is 58.5 m/s.

<h3>Minimum speed for the object not fall out of the circle</h3>

The minimum speed if given by tension in the wire;

T + mg = ma

T + mg = m(v²)/R

tension must be zero for the object not fall

0 + mg = mv²/R

v = √(Rg)

<h3>Final speed of the two mass after collision</h3>

Use the principle of conservation of energy

K.Ef  = K.Ei + P.E

¹/₂mvf² = ¹/₂mv² + mg(2R)

¹/₂vf² = ¹/₂v² + g(2R)

¹/₂vf² = ¹/₂(Rg) + g(2R)

vf² = Rg + 4Rg

vf² = 5Rg

vf = √(5Rg)

vf = √(5 x 2.8 x 9.8)

vf = 11.7 m/s

<h3>Initial speed of the dart</h3>

Apply principle of conservation of linear momentum for inelastic collision;

5v = vf(20 + 5)

5v = 11.7(25)

5v = 292.5

v = 58.5 m/s

Learn  more about linear momentum here: brainly.com/question/7538238

#SPJ1

3 0
2 years ago
A 2.0 kg bird lands on a 1.0 x 10^1 kg bit of tree bark sitting on a frictionless ice-covered pond. The bird’s initial horizonta
Bond [772]

Here in this type of question we can use momentum conservation

It is because we can see there is no external force on the system

So we can use momentum conservation principle

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

here we know that

m_1 = 2 kg

v_{1i} = 6 m/s

m_2 = 1 * 10^1 kg

v_{2i} = 0

now after bird sits on it then final speed of the both will be same

v_{2f} = v_{1f} = v m/s

2*6 + 1*10^1 * 0 = (2 + 1* 10^1) * v

12 = 12*v

v = 1 m/s

so final speed will be 1 m/s

7 0
2 years ago
Which star makes up Orion's knee to your right, or the end of his tunic?
lord [1]

Answer:

Betelgeuse and Rigel

Explanation:

100% correct

7 0
2 years ago
What is the external-internal pressure difference when the diver's lungs are at a depth of 6.1m (about 20ft)? assume that the di
Nesterboy [21]
Snorkel connects the diver's lungs with the air above the water. Because of this, the pressure inside the diver's lungs is the same as the atmospheric pressure.
The static pressure of a fluid is given with this equation:
P=\rho gh
The density of water is 1000kg/m^3.
P=1000\cdot 9.81 \cdot 6.1=59841$Pa
Standart atmospheric pressure is 101<span>325Pa. 
</span>The difference is:
\Delta P=101325-59841=41484 $Pa

8 0
3 years ago
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