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Brilliant_brown [7]
3 years ago
12

Twoâ cars, 405 kilometersâ apart, begin driving toward each other on aâ long, straight highway. one car travels 70 kilometers pe

r hour and the other 65 kilometers per hour. at the sameâ time, aâ canary, starting on oneâ car, flies back and forth between the two cars as they approach each other. if the canary flies 100 kilometers per hour and spends no time to turn around at eachâ car, how far has it flown when the carsâ collide?
Physics
1 answer:
mart [117]3 years ago
8 0
The space between the cars closes at (70+65)=135 km/hr. They collide in (405/135)=3 hours after they start moving. In 3 hours, the canary covers (100km/hr x 3)= 300 km.
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we can solve for the time t:

15\,\dfrac{\mathrm m}{\mathrm s}=\dfrac{49\,\mathrm m}t\implies t=3.3\,\mathrm s

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A roller coaster car starts from rest at the top of a hill 15 m high and rolls down to ground level. From there it starts into a
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velocity v = ?

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E_{tot}= mgh_{hill}

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7 0
3 years ago
A. A land speed car can decelerate at 9.8m/s. How long does it take the car to come to a complete stop from a run of 885 km/hr (
Nimfa-mama [501]

Answer:

A. 25.08 s

B. 3082.53 m

C. 3×10⁵ m/s²

Explanation:

A. Determination of the time.

This can be obtained as illustrated below:

Acceleration (a) = –9.8 m/s²

Initial velocity (u) = 245.8 m/s

Final velocity (v) = 0 m/s

Time (t) =.?

v = u + at

0 = 245.8 + (–9.8 × t)

0 = 245.8 – 9.8t

Collect like terms

0 – 245.8 = – 9.8t

– 245.8 = – 9.8t

Divide both side by –9.8

t = –245.8 / –9.8

t = 25.08 s

Therefore, it will take 25.08 s for the car to come to a complete stop.

B. Determination of the distance travelled by the car.

Acceleration (a) = –9.8 m/s²

Initial velocity (u) = 245.8 m/s

Final velocity (v) = 0 m/s

Distance (s) =?

v² = u² + 2as

0² = 245.8² + (2 × –9.8 × s)

0 = 60417.64 – 19.6s

Collect like terms

0 – 60417.64 = – 19.6s

– 60417.64 = – 19.6s

Divide both side by –19.6

s = –60417.64 / –19.6

s = 3082.53 m

Thus, the car travelled a distance of 3082.53 m before stopping completely.

C. Determination of the acceleration of the object.

Initial velocity (u) = 0 m/s

Final velocity (v) = 600 m/s

Distance (s) = 0.6 m

Acceleration (a) =?

v² = u² + 2as

600² = 0² + (2 × a × 0.6)

360000 = 0 + 1.2a

360000 = 1.2a

Divide both side by 1.2

a = 360000 / 1.2

a = 300000 = 3×10⁵ m/s²

7 0
3 years ago
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