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Harrizon [31]
3 years ago
12

A person throws a ball straight up in the air. The ball rises to a maximum height and then falls back down so that the person ca

tches it. Consider the ball while it is in the air. Which of the following statements are true? Just after the ball leaves the person's hand the direction of the acceleration is up. The acceleration is zero when the ball reaches its maximum height. The acceleration is about 9.8 m/s2 (down) when the ball is falling.
Physics
1 answer:
Lana71 [14]3 years ago
5 0

Answer:

The acceleration is about 9.8 m/s2 (down) when the ball is falling.

Explanation:

The ball at maximum height has velocity zero

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s² (positive downward and negative upward)

v=u+at\\\Rightarrow 0=u-9.8\times t\\\Rightarrow u=9.8t

The accleration 9.8 m/s² will always be acting on the body in opposite direction when the body is going up and in the same direction when the body is going down. The acceleration on the body will never be zero

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Answer:

1.a) 1 kJ

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     ratio 1:4

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2.a)  3.33 m/s2

Explanation:

1.a) bicycle's velocity =Displacement/time

                                   =100/20 m/s

                                   =5 m/s

bicycler's KE =1/2 *mass*(velocity)^2

                      =1/2*80*5^2

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1.b) bicycle's new velocity =200/20 m/s

                                   =10 m/s

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Ratio= KE 1 :KE new

        = 1 :4

1.c)  when bicycler's speed was doubled it increased the KE by 4 times (2^2). because In KE we consider the square of the speed , so the factor we increase the speed , the KE will get increased with the square value of it

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2.a) car acceleration = (20-0)/6 m/s2

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3 years ago
A sled is pulled up to the top of a hill. At thetop of the hill the sled is released from rest and allowed to coastdown the hill
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Answer:

a.) the speed at the bottom is greater for the steeperhill

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since the energy at the bottom of the steeper hilis greater

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5) A person holds a 1.7 kg bucket and lets it move down at
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Answer:

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Explanation:

Given parameters:

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Unknown;

Work done on the bucket by the person  = ?

Solution:

To solve this problem, we use the work done equation;

  Work done  = force x distance  = mgh

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  g is the acceleration due to gravity

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Now, insert parameters and solve ;

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PtichkaEL [24]

Answer:

1. bending of light in gravitational fields.

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