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Harrizon [31]
3 years ago
12

A person throws a ball straight up in the air. The ball rises to a maximum height and then falls back down so that the person ca

tches it. Consider the ball while it is in the air. Which of the following statements are true? Just after the ball leaves the person's hand the direction of the acceleration is up. The acceleration is zero when the ball reaches its maximum height. The acceleration is about 9.8 m/s2 (down) when the ball is falling.
Physics
1 answer:
Lana71 [14]3 years ago
5 0

Answer:

The acceleration is about 9.8 m/s2 (down) when the ball is falling.

Explanation:

The ball at maximum height has velocity zero

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s² (positive downward and negative upward)

v=u+at\\\Rightarrow 0=u-9.8\times t\\\Rightarrow u=9.8t

The accleration 9.8 m/s² will always be acting on the body in opposite direction when the body is going up and in the same direction when the body is going down. The acceleration on the body will never be zero

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Select Light for the type of wave, adjust the wavelength so that the light is red, and increase the amplitude of the light to th
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Answer:

here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa

Explanation:

As wee know that the amplitude of the wave will decide the energy of the wave

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u = \frac{1}{2}\epsilon_0E_0^2

now we have

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I = \frac{P}{4\pi r^2}

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5 0
3 years ago
Which of the following would produce the most power?
Fantom [35]

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

But Energy = mgh

Substituting into the equation, we have

Power = \frac {mgh}{time}

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

Power = \frac {10*9.8*10}{5} = 490 Watts

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6 0
2 years ago
it takes 90 j of work to stretch a spring 0.2 m from its equilibrium position. How muc work is needed to stretch it an additiona
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Work needed: 720 J

Explanation:

The work needed to stretch a spring is equal to the elastic potential energy stored in the spring when it is stretched, which is given by

E=\frac{1}{2}kx^2

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k is the spring constant

x is the stretching of the spring from the equilibrium position

In this problem, we have

E = 90 J (work done to stretch the spring)

x = 0.2 m (stretching)

Therefore, the spring constant is

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Now we can find what is the work done to stretch the spring by an additional 0.4 m, that means to a total displacement of

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Therefore, the additional work needed is

\Delta E=E'-E=810-90=720 J

Learn more about work:

brainly.com/question/6763771

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#LearnwithBrainly

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