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Gre4nikov [31]
3 years ago
6

Write the coefficients of:

Mathematics
1 answer:
Trava [24]3 years ago
7 0

Step-by-step explanation:

  1. Here x coefficients are 3y + 8y - Oy
  2. Here 5 coefficients are 61-7'n + 8p
  3. Here z coefficients are 0
  4. Here yz coefficients are 0
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I'll Mark Brainliest!!!!!!!!!!
skad [1K]

Answer:

see below  PLEASE GIVE BRAINLIEST

Step-by-step explanation:

2020 -2010 = 10 YEARS

375,000 X .09 = 33,750                  2011 VALUE  33750 + 375000 = 408,750

408750 X .09 = 36787.50               2012 VALUE  445537.50

445537.50 X .09 = 40,098.38         2013 VALUE  485635.88

485635.88 X .09 = 43707.23           2014 VALUE  529343.11

529343.11 X .09 = 47640.88            2015 VALUE  576983.99

576989.99 X .09 = 51928.56          2016 VALUE  628918.55

628918.55 X .09 = 56602.67          2017 VALUE 685521.22

685521.22 X .09 = 61696.91           2018 VALUE  747218.13

747218.13 X .09 = 67249.63           2019 VALUE 814467.76

814467.76 X .09 = 73,302.10          2020 VALUE $887,769.86

                                                   Rounded to the nearest dollar: $887,770.00

3 0
3 years ago
Which statements are true about quadrilaterals? Choose all answers that are correct. A. All 4-sided shapes are parallelograms. B
Katarina [22]
All 4-sided shapes is one of the features.
6 0
4 years ago
A driver's education course compared 1,500 students who had not taken the course with 1,850 students who had. Of those students
aivan3 [116]

Answer:

P-value is less than 0.999995 .

Step-by-step explanation:

We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.

Null Hypothesis, H_0 : p_1 = p_2 {means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}

Alternate Hypothesis, H_1 : p_1 > p_2 {means students who took the driver's education course were more likely to pass the written driver's exam the first time}

The test statistics used here will be two sample Binomial statistics i.e.;

                             \frac{(\hat p_1 - \hat p_2)-(p_1 - p_2)}{\sqrt{\frac{\hat p_1(1- \hat p_1)}{n_1} + \frac{\hat p_2(1- \hat p_2)}{n_2} } } ~ N(0,1)

Here, \hat p_1 = No. of students passed the exam ÷ No.of Students that had taken the course

 \hat p_1  = \frac{1150}{1850}            Similarly,  \hat p_2 = \frac{1440}{1500}          n_1 = 1,850       n_2 = 1,500

  Test Statistics = \frac{(\frac{1150}{1850} -\frac{1440}{1500})-0}{\sqrt{\frac{\frac{1150}{1850}(1- \frac{1150}{1850})}{1850} + \frac{\frac{1440}{1500}(1- \frac{1440}{1500})}{1500} } } = -27.38

P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)

Now, in z table the highest critical value given is 4.4172 which corresponds to the probability value of 0.0005%. Since our test statistics is way higher than this so we can only say that the p-value for an appropriate hypothesis test is less than 0.999995 .

6 0
3 years ago
A bag contains four red marbles, two green ones, one lavender one, three yellows, and one orange marble. HINT (See Example 7.] H
Murljashka [212]

Answer:  35

Step-by-step explanation:

Given : A bag contains four red marbles, two green ones, one lavender one, three yellows, and one orange marble.

Total = 4+2+1+3+1=11

To find sets of four marbles include none of the red ones, we need to exclude red marbles when we count the total number of marbles.

Then, the total marbles(exclude red) =11-4=7

Now, the combination of 7 marbles taking 4 at a time is given by :-

^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!3!}=35

Hence, the number of sets of four marbles include none of the red ones = 35

4 0
3 years ago
I need help with #8. I need to use the quadratic formula. I have a calculator that is programmed for the quadratic formula so al
GuDViN [60]

Answer:

  x = 14

Step-by-step explanation:

Extend line AB so that it intersects ray CE at point G. Then angles BGC and BAD are "alternate interior angles", hence congruent.

The angle at B is exterior to triangle BCG, and is equal to the sum of the interior angles at C and G:

  138 = (376 -23x) +(x^2 -8x)

Subtracting 138 and collecting terms we have ...

  x^2 -31x +238 = 0

For your calculator, a=1, b=-31, c=238.

__

<em>Additional comment</em>

You will find that the solutions to this are x = {14, 17}. You will also find that angle BCE will have corresponding values of 54° and -15°. That is, the solution x=17 is "extraneous." It is a solution to the equation, but not to the problem.

For x=14, the marked angles are A = 84°, C = 54°.

8 0
3 years ago
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