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2 years ago

12

Plz help me I will give u branist and follow u and also give u like plz help me

1 answer:

vazorg [7]2 years ago

7 0

Answer:

hi the answer is the first option, value assigned by the incorporation documents

please give brainliest

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What would be the most logical first step for solving this quadratic equation?

PolarNik [594]

Answer:

D

Step-by-step explanation:

So that you can have an equation equal to zero to solve for x

4 0

3 years ago

4 less than half a number is equal to 2 more than the number

xxMikexx [17]

Answer:

$-12$

Step-by-step explanation:

Let that number be $x$ . We can build an equation, and solve for $x$ .

$4$ less than half of $x$ is $x/2-4$ .

$2$ more than $x$ is $x+2$ .

We are given that the two quantities are equal, so we have that $x/2-4=x+2$ .

Adding $4$ to both sides gives $x/2=x+6$ .

Multiplying both sides by $2$ gives $x=2(x+6)=2x+12$ .

Subtracting $2x$ from both sides gives $-x=12$ .

Multiplying both sides by $-1$ gives $x=-12$ .

So, the number is $\boxed{-12}$ and we're done!

The check is left as an exercise to the reader.

3 0

2 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

I need help hdbcjsjfnfnfjfjffdbbfdncndnc

lbvjy [14]

$\frac{3}{15k+30} : \frac{6k}{5k^2+30k+40} = \frac{3}{15(k+2)} . \frac{5(k+2)(k+4)}{6k} = \frac{k+4}{6k}$

8 0

3 years ago

Find all the missing angles: a, b, c, d.

morpeh [17]

Answer:

a= 180-60-55=65

we know that the angle of a flat(?) ground would be 180, so we can take away the 60 and 55 to find a.

b=180-90-65=25

the sum of interior angle of a triangle would be 180, now we know what a is, also the right angle is 90, now we can take away the 90 and 65 to find b.

c=25

c is 25, because two angles on both sides of a X is the same

6 0

3 years ago