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Vikki [24]
3 years ago
15

You are studying the equilibirum between S8 and S2 gases at 0 celcius, you place a smaple of s2 in an otherwise empty, rigid con

tainer at an initial pressure of 3.-0 atm. wher eit reactsto form S8. at equilimrium, the partial pressure of s2 is 2.07 atm. calculate kp and kc.
Chemistry
1 answer:
Rainbow [258]3 years ago
5 0

Answer:

Kp and Kc are 0.01266 and 145.17, respectively.

Explanation:

Please check document attached.

Download docx
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\large \boxed{\text{4.63 atm}}

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T₁ = (   1 + 273.15) K = 274.15 K

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(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1} T_{1}} & = & \dfrac{p_{2}V_{2}}{n_{2} T_{2}}\\\\\dfrac{\text{2.02 atm}\times \text{736 mL}}{n _{1}\times \text{274.15 K}} & = &\dfrac{p_{2}\times \text{416 mL}}{n _{1}\times \text{355.15 K}}\\\\\text{5.423 atm} & = &1.171{p_{2}}\\p_{2} & = & \dfrac{\text{5.423 atm}}{1.171}\\\\ & = & \textbf{4.63 atm} \\\end{array}\\\text{The  new pressure will be $\large \boxed{\textbf{4.63 atm}}$}}

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