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WINSTONCH [101]
3 years ago
12

Which will conduct electricity: A solution of water and (NH₄)₂S or a solution of water and C₆H₁₂O₆?

Chemistry
1 answer:
TEA [102]3 years ago
8 0

Answer:

A solution of water and (NH₄)₂S

Explanation:

In a solution , the electricity can pass from it , if there is presence of free ions , as they are mobile and helps to conduct the electricity .

Therefore , the present of free ions is necessary for a solution to conduct electricity.

Hence, from the given options ,

  • Solution of water and (NH₄)₂S will conduct electricity as (NH₄)₂S will dissociate completely to the respective ions as they are dissolved in water , and the ions will help to conduct electricity.

Whereas ,

  • Solution of water and C₆H₁₂O₆ will not conduct electricity , as C₆H₁₂O₆ in water  will not dissociate completely , and does not produce ions , hence , won't conduct electricity.

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3 years ago
Identify the mixture of powdered charcoal and powdered sugar and suggest a technique for separating their components
mihalych1998 [28]
A- Identify the mixture:
The mixture of powdered charcoal and powdered sugar is considered as a homogeneous mixture. This means that you cannot identify the components with naked eye as they are uniformly distributed in the mixture.

B- Separate components:
You ca separate the charcoal powder from the sugar powder using the following steps:
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3 years ago
An empty container weighs 80.21 g. it is filled with 20.14 mL of an unknown liquid, and the total weight of the container and li
tatiyna

Answer:

1.242 g/mL

Explanation:

Step 1: Given data

Mass of the empty container (m₁): 80.21 g

Mass of the filled container (m₂): 105.22 g

Volume of the unknown liquid (V): 20.14 mL

Step 2: Calculate the mass of the liquid

The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.

m = m_2 - m_1 = 105.22g - 80.21 g = 25.01 g

Step 3: Calculate the density of the unknown liquid

The density of the liquid is equal to its mass divided by its volume.

\rho = \frac{m}{V} = \frac{25.01g}{20.14mL} = 1.242 g/mL

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