Write 2x^2+x-3 as (2x+3)(x-1)
When f(x)=(2x+3)(x-1) / g(x)= x-1
Both (x-1) (above and below) can be cut.
So answer is 2x+3
6/8 , just add both fractions together for the total, as they already have common denominators.
Answer:
a) 6
b) 6i
c) 6i
d) -6
Step-by-step explanation:
We are going to write down the numbers as a product of prime numbers and then proceed to solve:
Note: Remember that i = √-1 and that i²= -1
a) √9(√4)
√3² × √2² = 3 × 2 = 6
Thus, the answer is 6
b) √9 ×√-4
√3² x i√2² = 3 x 2i = 6i
Thus, the answer is 6i
c) √-9.√4
i√3² × √2² = 3i x 2 = 6i
Thus the answer is 6i
d) √-9.√-4
i√3² × i√2²
3i x 2i = -6
Thus the answer is -6
Answer:
it is B
Step-by-step explanation:
just combine the like factors
Answer:
12, 17, 24
Step-by-step explanation:
To find the first 3 terms, substitute n = 1, 2, 3 into the rule, that is
T₁ = 1² + 2(1) + 9 = 1 + 2 + 9 = 12
T₂ = 2² + 2(2) + 9 = 4 + 4 + 9 = 17
T₃ = 3² + 2(3) + 9 = 9 + 6 + 9 = 24