MgCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MgCl2 that dissolves.
MgCl2(s) --> Mg+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.098 mol MgCl2/1L × 2 mol Cl⁻ / 1 mol MgCl2 = 0.20 M
The answer to this question is [Cl⁻] = 0.20 M
Answer:
0.1 mol×L
Explanation:
Concentration= MOLES of SOLUTE / Volume of SOLUTION
So all we need to is to calculate the one quantity; Volume of SOLUTION has been specified to be 150 ml
So, MOLES of SOLUTE
x 100 x 10-L = ??mol; this was our starting solution.
And final CONCENTRATION=
0.15 . mol. 5 x 100 x 10-3L/
= 0.15 mol · L-1 150 x 10 3
=0.1 mol · L
To know if an equation is balanced you need to check and see how much of each molecule is on either side of the arrow. Right now you have 1-Ca, 2-H, 2-Cl on the left side of the arrow and 1-Ca, 2-Cl, and 2-H on the right side too. Because all the molecules are equal on both sides this means that the equation is balanced. So in front of the CaCl2 there is an assumed coefficient of 1. The answer is 1.