A sample of oxygen, o2, occupies a volume of 0. 65 l at 11°c under 0. 50 atm of pressure. (r = 0. 08205 latm/molk). how many mol
1 answer:
You might be interested in
Explanation:
The given precipitation reaction will be as follows.
Here, AgCl is the precipitate which is formed.
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity =
It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.
Molarity =
0.269 M =
no. of moles = 0.306 mol
As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.
No. of moles =
0.307 mol =
mass = 43.99 g
Thus, we can conclude that mass of precipitate produced is 43.99 g.