1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
schepotkina [342]
3 years ago
13

What is the mass in grams of 1.00 x 10 24 atoms of Mn?

Chemistry
2 answers:
hodyreva [135]3 years ago
8 0
A.
Sana po makatulong sagot ko hehe
Alex17521 [72]3 years ago
7 0
<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})
  2. [DA] Multiply/Divide [Cancel out units]:                                                           \displaystyle 91.2321 \ g \ Mn

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

You might be interested in
Which graph should be used to describe the
Tasya [4]
A I think that a bar graph would best represent this information.
3 0
3 years ago
Read 2 more answers
Difference between giant ionic structure,giant covalent structure and simple molecular structure and also covalent bonds and ion
Alex_Xolod [135]
Simple molecular biology
8 0
2 years ago
Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below.
zavuch27 [327]

15.63 mol. You need 15.63 mol HgO to produce 250.0 g O_2.

<em>Step 1</em>. Convert <em>grams of O_2 to moles of O_2</em>

Moles of O_2 = 250.0 g O_2 × (1 mol O_2/32.00 g O_2) = 7.8125 mol O_2

<em>Step 2</em>. Use the molar ratio of HgO:O_2 to convert <em>moles of O_2 to moles of HgO </em>

Moles of HgO = 0.8885 mol O_2 × (2 mol HgO/1 mol O_2) = <em>15.63 mol HgO</em>

7 0
3 years ago
Read 2 more answers
A learner was assigning oxidation numbers for different elements in the compounds OF2 and NaF. The learner assigned F an oxidati
77julia77 [94]

Answer: B. No, fluorine is always assigned an oxidation number of -1.

Explanation:

6 0
1 year ago
4 and 5 pls and thank uuu
PtichkaEL [24]

Answer:

4. -ol

5. cyclic ketone

Explanation:

biology stuff

sorry it's hard to explain

5 0
1 year ago
Other questions:
  • Which of the following is a function of the geosphere
    5·1 answer
  • A 1.555-g sample of baking soda decomposes with heat to produce 0.991 g Na2CO3. Refer to Example Exercise 14.l and show the calc
    10·1 answer
  • Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO mc0
    15·2 answers
  • Of the objects below, ________ is the most dense. Of the objects below, ________ is the most dense.
    12·1 answer
  • What is the concentration of hydrogen ions in a solution of ph = 4.0 ASAP PLEASE
    13·1 answer
  • How many molecules are ther in 3.5 moles of Corbin dioxide
    7·1 answer
  • Noble gases are.
    5·2 answers
  • The amount of material left after two half-lives is one-half of the original amount. ____________________
    12·2 answers
  • Can some one help me in this I hope this will be easy for you :)
    7·1 answer
  • A ________ alchohol has a -OH radical bonded to a central carbon atom.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!