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schepotkina [342]
3 years ago
13

What is the mass in grams of 1.00 x 10 24 atoms of Mn?

Chemistry
2 answers:
hodyreva [135]3 years ago
8 0
A.
Sana po makatulong sagot ko hehe
Alex17521 [72]3 years ago
7 0
<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})
  2. [DA] Multiply/Divide [Cancel out units]:                                                           \displaystyle 91.2321 \ g \ Mn

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

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soldier1979 [14.2K]
I would say d
Hope that helps :)
5 0
3 years ago
How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 4.46 atm and 45°C in the reaction shown below?
natka813 [3]

Answer:

8.1433 g of XeF₆  are required.

Explanation:

Balanced chemical equation;

XeF₆ (s) + 3H₂ (g)   →  Xe (g) + 6HF (g)

Given data:

Volume of hydrogen = 0.579 L

Pressure = 4.46 atm

Temperature = 45 °C (45+273= 318 k)

Solution:

First of all we will calculate the moles of hydrogen

PV = nRT

n = PV/ RT

n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K

n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹

n = 0.0995 mol

Mass of hydrogen:

Mass = moles × molar mass

Mass =  0.0995 mol × 2.016 g/mol

Mass =  0.2006 g

Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.

                                         H₂   :  XeF₆

                                          3    :    1

                                 0.0995   : 1/3× 0.0995 = 0.0332 mol

Now we will calculate the mass of XeF₆.

Mass = moles × molar mass

Mass = 0.0332 mol × 245.28 g/mol

Mass = 8.1433 g

4 0
3 years ago
Which buffer can be suitable to prepare a solution that needs to be buffered at ph 4?
zlopas [31]

Answer:

For pH= 4.00 :

Add 0.1 ml of 0.1 molar NaOH to 50 ml of 0.1 molar potassium hydrogen phthalate .

4 0
1 year ago
If it takes 2000 years to weather 1 cm of limestone, how long will it take to weather 5 cm of limestone?
Anna71 [15]

Answer:10,0000 years

Explanation:

If it takes 2000 years to weather 1cm of limestone

It will take 5*2000 years to weather 5cm of limestone. This gives us 10000 years.

3 0
3 years ago
Which best describes the molecules of an ideal gas
Serhud [2]
Options are as follow,

A)  <span>Constant volume, no intermolecular forces of attraction,energy loss in collisions 

B)  </span><span>No volume, strong intermolecular forces of attraction, perfectly elastic collisions

C)  </span><span>Constant volume, no intermolecular forces of attraction, energy gain during collisions

D)  </span><span>No volume, no intermolecular forces of attraction, perfectly elastic collisions

Answer:
            Option-D (</span>No volume, no intermolecular forces of attraction, perfectly elastic collisions) is the correct answer.

Explanation:
                   As we know there are no interactions between gas molecules due to which they lack shape and volume and occupies the shape and volume of container in which they are kept. So, we can skip Option-B. 
                   Secondly we also know that the gas molecules move randomly. They collide with the walls of container causing pressure and collide with each other. And these collisions are perfectly elastic and no energy is lost or gained during collisions. Therefore Option-A and C are skipped.
                   Now we are left with only Option-D, In option D it is given that ideal gas has no volume. This is true related to Ideal gas as it is stated in ideal gas theories that molecules are far apart from each other and the actual volume of gas molecules compared to volume of container is negligible. Hence, for ideal gas Option-D is a correct answer.
4 0
3 years ago
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