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lbvjy [14]
3 years ago
15

Which is one use of lasers?

Physics
2 answers:
Strike441 [17]3 years ago
7 0

Answer:

a laser sight for a weapon?

Explanation:

idfo

Levart [38]3 years ago
4 0
What are the options?
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If the moon moved closer to the earth, how would the gravitational force between them change?.
hichkok12 [17]

If the moon moved closer to the earth, The gravitational force between them will increase.

This can be understood by Newton's law of universal gravitation. This is usually stated as that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

F_{gravitation} = G\frac{M_{1} M_{2}}{r^{2} }

If the moon moved closer to earth, the distance between them will be reduced, and as the force of gravitation is inversely proportional to the distance between the masses, the gravitation force increases.

Learn more about gravitation force here

brainly.com/question/12528243

#SPJ4

7 0
2 years ago
Best summarizes the law of conservation of energy?
Charra [1.4K]
It states that no form of energy can be created nor destroyed over time it is just conserved. 

Official Definition- <span>In physics, the </span>law of conservation of energy<span> states that the total </span>energy<span> of an isolated system remains constant—it is said to be conserved over time. </span>Energy<span> can neither be created nor destroyed; rather, it transforms from one form to another.</span>
4 0
3 years ago
What is the component of d1 along the direction of d2?
aniked [119]
I don't know lol hahahahhahahahahahahahahahahahahaha
8 0
3 years ago
Use the data below to compute the gravitational force that the Sun exerts on Jupiter. (Use G = 6.67 x 10^-11 N · m²/kg².)
Mademuasel [1]

The gravitational force on two objects can be determined by the following equation:

F=G\frac{m_{1}m_{2}}{r^2}

Where G is the gravitational constant m1 is mass 1, m2 is the second mass nad r^2 is distance between these objects.  Therefore, let m1 = mass of Sun 1.99x10^30 kg, m2= mass of Jupiter 1.90x10^27 kg, r is the average distance between the Sun and Jupiter 7.78x10^11 m.  By plugging these values in we have:

F=6.67x10^{-11}\frac{(1.99x10^{30})(1.90x10^{27})}{(7.78x10^{11})^2}

F=4.1665x10^{23}

F=4.17x10^23 N


8 0
3 years ago
An iron anchor of density 7890.00 kg/m3 appears 299 N lighter in water than in air. (a) What is the volume of the anchor? (b) Ho
PtichkaEL [24]

Answer:

weigh is 2353.13 N

Explanation:

Given data

density = 7890.00 kg/m3

lighter =  299 N

to find out

the volume of the anchor and weigh in air

solution

from question we can say that

apparent weight = actual weight - buoyant force

we know weight = mg and buoyant force = water density × g

so volume of anchor is = actual weight - apparent weight / buoyant force

volume of anchor is = 299 / 1000 × 9.81

volume of anchor is = 0.0304791 m³

and

weight of anchor is mg

here mass m = density Fe g

density Fe = 7870 from table 14-1

so weight = 7870 × 0.0304791  × 9.81

weigh is 2353.13 N

7 0
4 years ago
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