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Charra [1.4K]
3 years ago
12

Which of the following describes a condition in which an individual would not hear an echo?

Physics
2 answers:
jolli1 [7]3 years ago
5 0

The answer is C. A sound reaches the ear and the reflected wave reaches the ear less than 0.1 second later

IrinaVladis [17]3 years ago
4 0
If the echo (the reflected sound) reaches your ear less than about
0.1 second after the original sound, your brain doesn't separate them,
and you're not aware of the echo even though it's there.

If the echo comes from, say, a wall, 0.1 second means you'd have to be
about  17 meters away from the wall.  If you're closer than that, then the
echo reaches you in less than 0.1 second and you're not aware of it.

A. 30 meters . . .
     No.  You hear that echo easily

B.  you're standing within range of both sounds . . .
     No. You hear that echo easily, if you're at least 17 meters from the wall.

C.  less than 0.1 second later . . .
     That's it.  The echo is there but your brain doesn't know it.

D.  21.5 meters
     No.  You hear that echo easily.

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PE = (|accepted value – experimental value| \ accepted value) x 100%

Explanation:

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99% of the earth´s atmosphere by mass is made up of only these elements: Nitrogen and oxygen.

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3 years ago
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If the window is 11 m above the ground, find the time the stone is in flight.
rjkz [21]
d=vi*t+(1/2)gt²

d=11 m
g=9.8 m/s²
vi=0 m/s

11 m=0 m/s*t+(1/2)9.8 m/s²t²
11 m=4.9 m/s²t²
t²=11 m / 4.9 m/s²
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Answer: the time the sone is in flight is 1.5 s
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HELP!!! The planet Mars has a mass about one-tenth the mass of Earth. Even though Mars has two moons, their tidal forces have a
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3 years ago
A wave of infrared light has a speed of 6 m/s and a wavelength of 12 m. What is the frequency of this wave?
givi [52]
I'll be happy to solve the problem using the information that
you gave in the question, but I have to tell you that this wave
is not infrared light.

If it was a wave of infrared, then its speed would be close
to 300,000,000 m/s, not 6 m/s, and its wavelength would be
less than 0.001 meter, not 12 meters.

For the wave you described . . .

             Frequency  =  (speed)  /  (wavelength)

                                 =  (6 m/s)  /  (12 m)

                                 =      0.5 / sec

                                 =      0.5 Hz .  

(If it were an infrared wave, then its frequency would be
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