How do waves shape Earth’s surface? HELP PLS 10 POINTS PLUS BRAINLEST

1 answer:

6 0

Answer:Waves shape the earths surface because they change the form of the coastal land form, meaning that when a wave is formed and moves they are also moving sand and rocks which can change the shape of the surface

Explanation:

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If a negatively charged particle enters a region of uniform magnetic field which is perpendicular to the particle's velocity, wi

lys-0071 [83]

Answer:

Same

Explanation:

While moving through a magnetic field in a direction perpendicular to a B-field, a continuous force experienced by a charged particle. If this magnetic field remains uniform, the force exerted also remains same and hence the velocity with which the particle is moving remains same. However, the particle is forced to move on a curved path until it forms a complete circle.

Hence, the kinetic energy remains the same because the speed is same

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2 years ago

if a ball is rolling at a velocity of 1.5 m/sec and has the momentum of 10.0 kg m/sec, what is the mass of the ball?

PolarNik [594]

Okay. There is a simple formula to go with this where:

p = mv

P: Momentum.
M: Mass.
V: Velocity

Sub the numbers in and solve for M.

10.0 = m(1.5)
10.0/1.5 = m
6.67 kg = m

Therefore the mass of the ball is 6.67kg.

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2 years ago

a physics student throws a stone horizontally off a cliff. one second later, he throws a second identical stone in exactly the s

Virty [35]

The second stone hits the ground exactly one second after the first.

The distance traveled by each stone down the cliff is calculated using second kinematic equation;

$h = v_0_yt + \frac{1}{2} gt^2$

where;

t is the time of motion
$v_0_y$ is the initial vertical velocity of the stone = 0

$h = \frac{1}{2} gt^2$

The time taken by the first stone to hit the ground is calculated as;

$t_1 = \sqrt{\frac{2h}{g} }$

When compared to the first stone, the time taken by the second stone to hit the ground after 1 second it was released is calculated as

$t_2 = \sqrt{\frac{2h}{g} } + 1$