The direction of the friction force F exerted by the horizontal surface on the crate will be in the left direction.
<h3>How to depict the force?</h3>
From the information given, the 85-lb force P is applied to the 200-lb crate, which is stationary before the force is applied.
mg = 200 × 0.2248 × 9.8 = 440.608
The static friction force will be:
= 0.5 × 440.608
= 220.304N
Therefore, the static friction is greater than the force applied. Therefore, there'll be a static friction acting on the box on the left direction.
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Answer:
0N
Explanation:
Is the car is moving in a constant direction with constant speed, the composite force is null. We know what because any object that nonzero composite force is applied to will accelerate in the direction of the force, and this one doesn't.
Answer:
pressure on a given day
Explanation:
because you can't find pressure in a day
Answer:
C.subscript
Explanation:
The number 3 is a subscript on the hydrogen atom in ammonia NH₃.
Subscript is a lower notation on a reference atom. It states the number of hydrogen atom covalently bonding with the single N atom.
The superscript is located up. For example P², the 2 is a superscript.
The coefficient is the number before a compound or atom e.g 2C represents two atoms of Carbon.
The numerator is the upper value in a fraction. The denominator is the one beneath.
Answer:
D) The ball exerts a force on the wall and the wall exerts a force back.
Explanation:
Newton's third law of motion states that:
"When an object A exerts a force on another object B, then object B exerts an equal and opposite force on object A"
In this problem, we can identify (for instance) object A with tha ball and object B with the wall. Therefore, if we apply Newton's third law, we get:
The ball (object A) exerts a force on the wall (object B), therefore the wall (object B) exerts an equal and opposite force on the ball (object A). So, option D is the correct one.
