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bija089 [108]
3 years ago
9

To find the area of a trapezoid, use the expression ½h(b¹ + b²), where h represents the height, b, represents the length of the

top base, and by represents the length of the bottom base. What is the area of the trapezoidal table?​
Mathematics
1 answer:
grandymaker [24]3 years ago
3 0

is there supposed to be an image?? (comments, ill give answer if not, im

just confused)

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Length of a rectangle is four times its width. If the perimeter is 100 m, what is the area in square cm?
melisa1 [442]

Set the width to be x. Thus, the length is 4x.

The perimeter is 2(x+4x)=100, so x=10.

Plugging in x=10, you get that 4x=40.

So, the area of the rectangle is 400 m^2.

Because there are 100 centimeters in a meter and you are asking for area, you must multiply by 100^2 to get 4000000 cm^2.


6 0
3 years ago
If the factors of a quadratic function are (x + 2) and (x − 9), what are the x-intercepts of the function?
Zielflug [23.3K]

Answer: D. (-2,0) and (9,0)

Step-by-step explanation:

When you equate the factors to 0 you get

(X+2) = 0

X = -2

(X-9) = 0

X= 9

Here the Y value is 0 as you find the factors of x when the Y value is 0.

So the answer is (-2,0) and (9,0)

8 0
3 years ago
Anyone help? don’t understand this question?
Anit [1.1K]

Answer:

Step-by-step explanation:

Let the fraction is "x"

hence putt in box we get,

1-x=3/7

x=1-3/7

taking LCM

x=7-3/7

x=4/7 Ans....

7 0
3 years ago
Read 2 more answers
Slope is -1/2 and y-intercept is -2
miskamm [114]
Y= -1/2x-2
this is the y=mx+b equation of a line.
3 0
3 years ago
Find a polynomial of degree 3 with real cofficients and zeros of -3,-1,4 for which f(-2)=24​
konstantin123 [22]

\bf \textit{zeros at } \begin{cases} x = -3\implies &x+3=0\\ x = -1\implies &x+1=0\\ x = 4\implies &x-4=0 \end{cases}\qquad \implies (x+3)(x+1)(x-4)=\stackrel{y}{0} \\\\\\ (x^2+4x+3)(x-4)=0\implies x^3~~\begin{matrix}+ 4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+3x~~\begin{matrix} -4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-16x-12=0 \\\\\\ x^3-13x-12=0

we know that f(-2) = 24, namely when x = -2, y = 24, let's see if that's true

\bf x^3-13x-12=y\implies \stackrel{x = -2}{(-2)^3-13(-2)-12}=y \\\\\\ -8+26-22=y \implies 6=y

darn!! no dice.... hmmmm wait a second.... 4 * 6 = 24, if we could just use a common factor of 4 on the function, that common factor times 6 will give us 24, let's check.

\bf 4(x^3-13x-12)=y\implies \stackrel{x = -2}{4[~~(-2)^3-13(-2)-12~~]}=y \\\\\\ 4[~~-8+26-22~~]=y\implies 4[6]=y\implies 24=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 4x^3-52x-48=y~\hfill

4 0
4 years ago
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