Step-by-step explanation:
Any positive number can. be a side length. It cannot pass 7 because a square with 49 sqr lnches as a area has side lengths with the measures of 7.
The perimeter of a rectangle is 2(w+l)
We can find the lengths by setting the equation equal to 12.
12=2(w+l)
12÷2=(2(w+l))÷2
6=w+l
6=1+5
6=2+4
6=3+3
These are the lengths of the sides of three rectangles with a perimeter of 12 units.
You're probably wondering why the third one has two of the same number, because that's usually how the lengths of sides of squares are, not rectangles.
Well, there's this wonderful thing about the rules of shapes.
<em>Squares ARE rectangles.
</em>Because they follow the rules for a rectangle, squares are also classified as rectangles.
So, the rectangle side lengths are as follows:
1 unit by 5 units
2 units by 4 units
3 units by 3 units
<em />
Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5
Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:
4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)
Let 's now solve the system
4y=3x + 20
4x-3y=-1
We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:
12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)
Then we have
12y = 9x + 60
-12y =-16x - 4
If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8
We were given equations
</span><span>y=3/4X+5
4x-3y=-1
We can subst. x=8 into either of these eqn's to find y. Let's try the first one:
y = (3/4)(8)+5 = 6+5=11
Then x=8 and y=11.
You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?</span>
11/12 - 7/12 = 4/12 = 1/3
please give brainliest
