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sveticcg [70]
3 years ago
5

¿Qué proporción deberían guardar los platos de una prensa hidráulica para que, aplicando 40N de fuerza en el plato menor, podamo

s levantar un objeto de 40Kg en el plato mayor?
Physics
1 answer:
9966 [12]3 years ago
3 0

Answer:

El área de la placa más grande es aproximadamente 9,81 veces el tamaño del área de la placa más pequeña

Explanation:

Los parámetros dados son;

La fuerza aplicada sobre la placa más pequeña, F = 40 N

El culo del objeto levantado en la placa más grande, m = 40 kg

El peso del objeto, W = 40 kg × 9,81 m / s² = 392,4 N

Tenemos la presión en el plato pequeño = La presión en el plato más grande

Por lo tanto;

F / A₁ = W / A₂

Dónde;

A₁ = El área del plato pequeño

A₂ = El área de la placa más grande

Por lo tanto, obtenemos;

40 N / (A₁) = 392,4 N / (A₂)

A₂ / A₁ = 392,4 N / (40 N) = 9,81

∴ A₂ = A₁ × 9,81

El área de la placa más grande, A₂ = 9,81 (9,81 m / s² ≈ g) multiplicado por el área de la placa más pequeña A₁.

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