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3 years ago

a hotgas is injected into at engine at 573 k and exhausts at 343 k. what is the highest efficiency of thisengine?

Physics

1 answer:

Dovator [93]3 years ago

4 0

Answer:

230k

Explanation:

energy capacity maximum is 573 total available. 343k of that energy is present at release and subsequent loss leaving max used energy of 230k.

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Some people believe that the Moon’s phases are caused by Earth’s shadows on the Moon. Is this true?

emmasim [6.3K]

No thats false. If your trying to say is true that people BELIEVED that then yes its true people believed it but if your talking about that question then its false

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4 years ago

A 16000 kg railroad car travels along on a level frictionless track with a constant speed of 23.0 m/s. A 5400 kg additional load

Alisiya [41]

Answer:

The speed of the car when load is dropped in it is 17.19 m/s.

Explanation:

It is given that,

Mass of the railroad car, m₁ = 16000 kg

Speed of the railroad car, v₁ = 23 m/s

Mass of additional load, m₂ = 5400 kg

The additional load is dropped onto the car. Let v will be its speed. On applying the conservation of momentum as :

$m_1v_1=(m_1+m_2)v$

$v=\dfrac{m_1v_1}{m_1+m_2}$

$v=\dfrac{16000\ kg\times 23\ m/s}{(16000+5400)\ kg}$

v = 17.19 m/s

So, the speed of the car when load is dropped in it is 17.19 m/s. Hence, this is the required solution.

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3 years ago

10. What is the acceleration due to gravity at a location

kherson [118]

The answer is 3) 3.00 m/s2

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3 years ago

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garri49 [273]

Answer:

Explanation:

I hope this is what you need

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3 years ago

Read 2 more answers

Pls help me solve this<br><br><br><br>

musickatia [10]

Answer:

a) The uniform velocity travelled by the car is 10 meters per second.

(Point b has been erased by the user)

c) The distance travelled by the car with uniform velocity is 100 meters.

Explanation:

a) Calculate the uniform velocity travelled by the car:

The uniform velocity is the final velocity ( $v$ ), in meters per second, of the the uniform accelerated stage:

$v = v_{o} + a\cdot t$ (1)

Where:

$v_{o}$ - Initial velocity, in meters per second.

$a$ - Acceleration, in meters per square second.

$t$ - Time, in seconds.

If we know that $v_{o} = 0\,\frac{m}{s}$ , $a = 2\,\frac{m}{s^{2}}$ and $t = 5\,s$ , then the uniform velocity is:

$v = 0\,\frac{m}{s} + \left(2\,\frac{m}{s^{2}} \right)\cdot (5\,s)$

$v = 10\,\frac{m}{s}$

The uniform velocity travelled by the car is 10 meters per second.

(Point b has been erased by the user)

c) The distance travelled by the car ( $\Delta x$ ), in meters, with uniform velocity is calculated by the following kinematic expression:

$\Delta x = v\cdot t$ (2)

If we know that $v = 10\,\frac{m}{s}$ and $t = 10\,s$ , then the distance travelled is:

$\Delta x = \left(10\,\frac{m}{s} \right)\cdot (10\,s)$

$\Delta x = 100\,m$

The distance travelled by the car with uniform velocity is 100 meters.

4 0

3 years ago