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2 years ago

a hotgas is injected into at engine at 573 k and exhausts at 343 k. what is the highest efficiency of thisengine?

Physics

1 answer:

Dovator [93]2 years ago

4 0

Answer:

230k

Explanation:

energy capacity maximum is 573 total available. 343k of that energy is present at release and subsequent loss leaving max used energy of 230k.

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2 years ago

Consider the uniform electric field \vec{E} =(4.00~\hat{j}+3.00~\hat{k})\times 10^3~\text{N/C} E ⃗ =(4.00 j ^ +3.00 k

Tema [17]

Answer:

Electric flux, $\phi=6.668\times 10^4\ Nm^2/C$

Explanation:

It is given that,

Electric field, $E=(4j+3k)\times 10^3\ N/C$

We need to find the electric flux through a circular area of radius 2.66 m that lies in the xy-plane. $A=Ak$

The electric flux is given by :

$\phi=E{\cdot}A$

$\phi=(4j+3k)\times 10^3{\cdot}Ak$

Since, k.k=i.i=j.j = 1

So,

$\phi=3\times 10^3\times \pi\times (2.66)^2\ k$

$\phi=6.668\times 10^4\ Nm^2/C$

So, the electric flux through a circular area is $\phi=6.668\times 10^4\ Nm^2/C$ .Hence, this is the required solution.

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3 years ago

I REALLY NEED HELP PLEASE!!! CAN SOMEONE ANSWER THIS? At 0 ºC, some amount of energy is required to change 1 kg of water from a

Nezavi [6.7K]

Answer:

C)It would require more energy to change solid water into liquid water because there are more molecules in this larger piece of ice.

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3 years ago

Read 2 more answers

A gas expands and does PV work on its surroundings equal to 319 J. At the same time, it absorbs 136 J of heat from the surroundi

LiRa [457]

Answer:

The change in energy of the gas during the process is $-1.83\times 10^{2}$ joules.

Explanation:

We can represent this process by the First Law of Thermodynamics, in which gas does work on its surroundings and absorbs heat from there to describe its change in energy. In other words:

$Q_{in} - W_{out} = \Delta E$

Where:

$Q_{in}$ - Heat absorbed by the gas, measured in joules.

$W_{out}$ - Work done by the gas, measured in joules.

$\Delta E$ - Change in energy, measured in joules.

If we know that $Q_{in} = 1.36\times 10^{2}\,J$ and $W_{out} = 3.19\times 10^{2}\,J$ , the change in energy of the gas is:

$\Delta E = 1.36\times 10^{2}\,J-3.19\times 10^{2}\,J$

$\Delta E = -1.83\times 10^{2}\,J$

The change in energy of the gas during the process is $-1.83\times 10^{2}$ joules.

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2 years ago

F an object has a mass of 200 kg and a weight of 1000 N, what is g?

jeka94

Answer:

g = 5 m/s square

Explanation:

Weight(W), Mass(m), Gravity(g)

W = mg

1,000N = 200g

g = 1000/200

g = 5 m/s square

7 0

2 years ago