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sleet_krkn [62]
3 years ago
6

In the winter activity of tubing, riders slide down snow covered slopes while sitting on large inflated rubber tubes. To get to

the top of the slope, a rider and his tube, with a total mass of 84 kg , are pulled at a constant speed by a tow rope that maintains a constant tension of 350 N .
Physics
1 answer:
goldenfox [79]3 years ago
7 0

Answer:

17304 J

Explanation:

Complete statement of the question is :

In the winter activity of tubing, riders slide down snow covered slopes while sitting on large inflated rubber tubes. To get to the top of the slope, a rider and his tube, with a total mass of 84 kg , are pulled at a constant speed by a tow rope that maintains a constant tension of 350 N .

Part A

How much thermal energy is created in the slope and the tube during the ascent of a 30-m-high, 120-m-long slope?

Solution :

T = tension force in the tow rope = 350 N

L  = length of the incline surface = 120 m

W_{t}  = work done by tension force = ?

The tension force acts parallel to incline surface, hence work done by tension force is given as

W_{t} = T L\\W_{t} = (350) (120)\\W_{t} = 42000 J

h = height gained by the rider = 30 m

m = total mass of rider and tube = 84 kg

Potential energy gained is given as

U = mgh\\U = (84) (9.8) (30)\\U = 24696 J

Q  = Thermal energy created

Using conservation of energy

Q = W_{t} - U\\Q = 42000 - 24696\\Q = 17304 J

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Answer:

a) x = 0.200 m

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by relation for electric field we have following relation

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\frac{0.5}{x} = 1+ \sqrt{\frac{47}{21}}

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6 0
3 years ago
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Answer:

1025.64 N/m²

Explanation:

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From the question,

P = F/A........................ Equation 1

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Given: F = 10 Newtons, A = 15 Squared Inches = (15×0.00065) = 0.00975 m²

Substitute these values into equation 1

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