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Ray Of Light [21]
2 years ago
12

What is the x? please answer!

Mathematics
1 answer:
zzz [600]2 years ago
8 0

Answer:

x = 2

Step-by-step explanation:

1. distribute 9 in 9(x+1)

9x + 9 = 25 + x

2. subtract x from the right side to isolate x onto one side

8x + 9 = 25

3. subtract 9 from the left side

8x = 16

4. divide both sides by 8 to get x alone

x = 2

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A company makes windows for use in homes and commercial buildings. The standards for glass thickness call for the glass to avera
guajiro [1.7K]

The question is incomplete. The complete question follows.

A company makes windows for use in homes and commercial builidings. The standards for glass thickness call for the glass to average 0.325 inch with a standard deviation equal to 0.065 inch. Suppose a random sample of n=44 windows yield a sample mean of 0.337 inch. Complete parts a and b.

a. What is the probability of x ≥ 0.337 if the windows meet the standards?

b. Based on your answer to part a, what would you conclude about the population of windows? Is it meeting the standards? (A result is unusual if it has a probability less than 0.05)

Answer and Step-by-step explanation: To answer this question, use <u><em>Central Limit Theorem</em></u>: it states regardless of the original population distribution, if the sample size is large enough, the sample mean distribution will approach a normal distribution.

The calculations for the CLT is given by normalizing the distribution, i.e.:

z=\frac{x-\mu}{\sigma/\sqrt{n} }

where

z is z-score

x is the sample mean

μ is population mean

σ is standard deviation of the population

n is the number of individuals in the sample

Calculating z-score for the window maker company:

z=\frac{0.337-0.325}{0.065/\sqrt{44} }

z=\frac{0.012}{0.0098}

z = 1.22

Using the z-score table, we found the probability:

P = 0.8888

As it is a "more than situation":

P(x≥0.337) = 1 - 0.8888

P(x≥0.337) = 0.1112  or 11.12%

a. Probability of x≥0.337 if the windows meet the standards is 11.12%.

b. Comparing results, probability of x≥0.337 is bigger than 0.05:

0.1112 > 0.05

So, we can conclude that the random sample of n=44 is meeting the standards estipulated.

7 0
2 years ago
A car rental agency rents cars for $26.20 per day plus $0.35 per mile driven. Your travel budget is $200. Write an inequality th
laila [671]

For this case we have to:

x: Represents the number of miles that can be traveled in a day

We have that the cost of daily car rental is given by the following expression:

26.20 + 0.35x

If the person has a budget of $200 then we have to:

26.20+0.35x\leq200\\0.35x\leq200-26.20\\0.35x\leq173.8\\x\leq\frac{173.8}{0.35}\\x\leq496.57

Thus, you can travel 496 miles in one day.

Answer:

26.20 + 0.35x \leq200

6 0
3 years ago
How to graph y=7x-1 using the y
kirill [66]
Plot the y-intercept (0,-1) and then from that point go up seven and to the right one. Plot that point, then draw the line between the two points.

Hope this helped! Good luck! :)
8 0
3 years ago
Choose a method you prefer to solve for a system of linear equations.<br> 2x + 4y = -4<br> 2x-y=6
Artyom0805 [142]

Answer:

Elimination

x = 2

y = -2

Step-by-step explanation:

Elimination

2x + 4y = -4

2x - y = 6

Subtract the second equation from the first

5y = -10

Divide both sides by 5

y = -2

---------------------

Substitute for y = -2 in the second equation

2x - -2 = 6

2x + 2 = 6

subtract 2 from both sides

2x = 4

Divide both sides by 2

x = 2

7 0
2 years ago
Solve for w. | – w|≥2 Write a compound inequality like 1 &lt; x &lt; 3 or like x &lt; 1 or x &gt; 3. Use integers, proper fracti
Eduardwww [97]

Answer:

-2 \geq w \geq 2

Step-by-step explanation:

Given

|-w| \geq 2

Required

Solve for w

|-w| \geq 2

In absolution functions;

|-w| = |w|

So, the given expression can be rewritten as

|w| \geq 2

Removing the absolute sign, will gibe

w \geq 2 or w \leq -2

When the second inequality os rewritten, it gives

w \geq 2 or -2 \geq w

Reorder both inequalities

-2 \geq w or w \geq 2

Lastly, both inequalities are combined

-2 \geq w \geq 2

6 0
3 years ago
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