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mash [69]
3 years ago
10

Could someone answer this?

Physics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

Here the circuit in which a 4Ω resistor resistor is connected in series and two 8Ω resistor resistors are connected in parallel. Also, ammeter and voltmeter connected in series and parallel circuit respectively.

Now,

The maximum power of each resistance is 16 W

The 4Ω resistor is linked in series with the circuit.

so, P o w e r = I

two

R, here i is the current through the resistor resistor R

1 6 = I

two

∗ 4 Ω

i = 2A

Now 2A passes through parallel resistors of 8Ω resistance.

we know that, in parallel, the potential difference must be constant,

the current is divided into two parts, because the same resistance current in each resistance will be half. then the current through each resistor in parallel is

2 A

two

.

= 1 A

So finally the current through the 4Ω resistor = 2 A

current through each 8Ω resistor = 1 A

Explanation:

I hope this answer has helped you

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You toss a ball straight up by giving it an initial upward velocity of 18 m/s. What is the velocity of the ball 0.50 s after you
Dmitriy789 [7]

We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

Acceleration = - 9.81m/s^2 . Negative means acceleration is towards center of planet Earth.

Time taken = 0.50 seconds

Initial velocity = 18 m/s

v = u+at

v = 18-9.81*0.50

   = 13.095 m/s

So velocity after 0.50 seconds is 13.095 m/s

4 0
4 years ago
Consult Multiple-Concept Example 11 for background material relating to this problem. A small rubber wheel on the shaft of a bic
Papessa [141]

Answer:

Emf=24.4V

Explanation:

From the question we are told that:

Angular speed \omega=40*\omega'

Radius r=0.33m

No. Turns N=163

Area A= 3.23 * 10^{-3} m^2

Magnetic field. B=0.0948T

Acceleration a=0.60m/s^2

Time t=6.72s

Generally the equation for momentum is mathematically given by

\omega'=\omega_o+\frac[a}{r}t

\omega'=0+\frac{0.60}{0.33}*6.72

W=12.22rad/s^2

Therefore

\omega=Aw

\omega=12.22*40

\omega=488.7rads/s

Generally the equation for Peak emf is mathematically given by

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Emf=163*0.0948* 3.23 * 10^{-3} m^2*488.7rads/s

Emf=24.4V

3 0
3 years ago
A 50.0 kg object is moving at 18.2 m/s when a 200 N force is applied opposite the direction of the objects motion, causing it to
Gekata [30.6K]

Answer:

t = 1.4[s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

P=m*v\\or\\P=F*t

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 50 [kg]

v = velocity [m/s]

F = force = 200[N]

t = time = [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

(m_{1}*v_{1})-F*t=(m_{1}*v_{2})

where:

m₁ = mass of the object = 50 [kg]

v₁ = velocity of the object before the impulse = 18.2 [m/s]

v₂ = velocity of the object after the impulse = 12.6 [m/s]

(50*18.2)-200*t=50*12.6\\910-200*t=630\\200*t=910-630\\200*t=280\\t=1.4[s]

3 0
3 years ago
In a Rutherford scattering experiment, an alpha particle is accelerated toward a stationary silver nucleus. If the closest appro
lys-0071 [83]

Answer:

Initial Kinetic energy of alpha particle is  9.45x10⁻¹³ J .

Explanation:

The distance at which the initial kinetic energy of the particle is equal to the potential energy is known as closest distance. As it is Rutherford scattering, so it is a coulomb potential energy.

Let K be the initial kinetic energy of alpha particle and r be the closest approach distance. So,

Initial Kinetic Energy = Coulomb Potential Energy

K = \frac{k\times2e\times{Ze}}{r }

Here, k is constant, e is charge of electron and Z is the atomic number of silver.

Put 9x10⁹ N m²/C² for k, 1.6x10⁻¹⁹ C for e, 47 for Z and 22.9x10⁻¹⁵ m for r in the above equation.

K = \frac{9\times10^{9}\times{1.6}\times10^{-19}\times{1.6}\times10^{-19}\times2\times47}{22.9\times10^{-15} }

K = 9.45x10⁻¹³ J

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4 years ago
What net force would be required for a 50.5 kg wolf to accelerate at 5.0 m/s^2
Basile [38]

Answer:

\boxed {\boxed {\sf 252.5 \ Newtons }}

Explanation:

Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.

F=m*a

The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:

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Substitute the values into the formula.

F= 50.5 \ kg * 5.0 \ m/s^2

Multiply.

F=252.5 \ kg*m/s^2

  • 1 kilogram meter per square second is equal to 1 Newton.
  • Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.

F= 252.5 \ N

The force required is <u>252.5 Newtons</u>.

4 0
3 years ago
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