Ask question

Ask question

All categories

3 years ago

11

A group of students is measuring the change in momentum of an object. Which set of lab equipment would be most in measuring the

momentum of an object?

1 answer:

a_sh-v [17]3 years ago

4 0

Answer:

The momentum of an object is defined as the mass of the object times the velocity of the object, as P = m*v.

So the equipment needed would be:

Something to measure the mass of the object, like a balance.

Something to measure the speed of the object, like a doppler radar, or a simpler thing may be a cronometer, with that you can measure the amount of time that the object needs to travel a given distance, and with that you can obtain the speed of the object.

Now you can notice that speed is different than velocity, this is true, velocity is a vector, so this has a direction, then you need something to fix the direction in which the object moves, in this way you can determine the velocity.

You might be interested in

The ultimate source of energy that powers the sun is

Daniel [21]

The ultimate source of energy that powers the sun is the Mass energy of hydrogen fusing into helium, there is no other process than the annihilation of mass to give energy that has been advocated by Albert Einstein and it is capable of keeping the sun alive.

6 0

2 years ago

Read 2 more answers

An engine has a hot-reservoir temperature of 980 K and a cold-reservoir temperature of 570 K. The engine operates at three-fifth

hram777 [196]

Answer:

efficiency of engine is 0.21

Explanation:

given:

Th=980 K

Tc=570 K

since efficiency of engine is given as:

n=3/5*n_m

=3/5(1-Tc/Th)

=0.21

efficiency of engine is 0.21

7 0

3 years ago

Read 2 more answers

A 1350 kg car travels at 12 m/s. What is it's kinetic energy

Lana71 [14]

Hello!

A 1350 kg car travels at 12 m/s. What is it's kinetic energy ?

We have the following data:

m (mass) = 1350 kg

v (velocity) = 12 m/s

KE (kinetic Energy) = ? (in Joule)

Formula to calculate kinetic energy:

$\boxed{KE = \dfrac{1}{2} *m*v^2}$

Solving:

$KE = \dfrac{1}{2} *m*v^2$

$KE = \dfrac{1}{2} *1350*12^2$

$KE = \dfrac{1}{2} *1350*144$

$KE = \dfrac{194400}{2}$

$\boxed{\boxed{KE = 97200\:Joule}}\:or\:\boxed{\boxed{KE = 97.2\:kJ}}\Longleftarrow(kinetic\:energy)\:\:\:\:\:\:\bf\blue{\checkmark}$

_______________________

$\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

5 0

2 years ago

Which statement about sodium chloride is correct?

kvasek [131]

Answer:

the sodium atom and the chlorine atoms share electrons to form ionic bonds

5 0

2 years ago

The gravitational force of attraction be-

Sliva [168]

Answer:

2.15 m

Explanation:

Newton's Law of Universal Gravitation:

$\displaystyle F_g = G \frac{m_1 m_2}{r^2}$

$\displaystyle F_g$ is the gravitational force of attraction

$\displaystyle G$ is the universal gravitational constant

$m_1$ and $m_2$ are the two masses of the two objects

$\displaystyle r$ is the distance between the centers of the two objects.

List the known values:

$\displaystyle F_g = 3.47 \cdot 10^-^8 \ \text{N}$
$\displaystyle G = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2}$
$\displaystyle m_1 = 44.8 \ \text{kg} \\ m_2 = 53.9 \ \text{kg}$
$\displaystyle r =\ ?$

Plug these values into the equation:

$\displaystyle 3.47 \cdot 10^-^8 \ \text{N} = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2} \frac{(44.8 \ \text{kg})(53.9 \ \text{kg})}{r^2}$

Notice that the units $\displaystyle \text{N}$ , $\displaystyle \text{kg}^2$ , and $\displaystyle \text{m}$ cancel out. We are left with the unit $\displaystyle \text{m}$ for radius r.

Get rid of the units to make the problem easier to read.

$\displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(44.8)(53.9) \ }{r^2}$

Multiply the masses together.

$\displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(2414.72)}{r^2}$

Multiply the gravitational constant and the masses together.

$\displaystyle 3.47 \cdot 10^-^8= \frac{1.61134265\cdot 10^-^7}{r^2}$

Solve for $r^2$ by dividing both sides by 3.47 * 10^(-8) and moving $r^2$ to the left.

$\displaystyle r^2 = \frac{1.61134265\cdot 10^-^7}{3.47\cdot 10^-^8}$
$r^2 = 4.64363876$

Take the square root of both sides.

$r=2.154910383$

The students are sitting about 2.15 m apart from each other.

4 0

2 years ago