$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=\textit{original amount deposited}\to &\$850\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, so four times}
\end{array}\to &4\\

t=years\to &3
\end{cases}$

7 0

3 years ago

Evaluate the sum of the finite geometric series.<br> 1+2+4+8+...+128

Wittaler [7]

S = a*((1 - r^(n+1))/(1-r)) S = 1*((1 - 2^(7+1))/(1-2)) S = 1*((1 - 2^8)/(1-2)) S = 1*((1 - 256)/(1-2)) S = 1*((-255)/(-1)) S = 255 So 1+2+4+8+...+128 = 255

7 0

3 years ago

Jean has a car, Last year, cost of running her car £4200 and £0.16. for every kilmetre the car travelled.

Eduardwww [97]

I hope this helps you

5772-4200=1572

1572÷0,16

9825

8 0

3 years ago