The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.
This means that Purple #1 is <u>a redder</u> shade of purple than Purple #2.
Purple #2 is <u>a bluer</u> shade of purple than Purple #1.
Step-by-step explanation:
The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.
Making blue's quantity as 3 parts for purple #1 implies red part becomes 1.5 to maintain the ratio 1:2
Purple #1 has 1/3 parts red and 2/3 parts blue. Purple #2 has 1/4th part red and 3/4th part blue.
Hence, Purple #1 is <u>a redder</u> shade of purple than Purple #2.
From the above explanation, <u>Purple #2</u> is a bluer shade of purple than Purple #1.
<em>Sure hopes this helps you :)</em>
<em></em>
<h3><em>
//❀ ❀//</em></h3>
Answer:
Option B
Step-by-step explanation:
Taking the derivative of the residual function, then applying the normal equation:
[a; b] = (X'*X)^(X'*y)
with
X = [1 1; 2 1; 3 1; 4 1; 5 1]
X' is transpose of X
y = [11; 8; 4; 1; 0]
[a; b] = [-2.9 13.5]
the answer is 4.8. Your welcome
Starting from the fundamental trigonometric equation, we have

Since
, we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

Plugging the numbers, we have

Now, just recall that

to deduce

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