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2 years ago

15

The ratio of men and women at a class is 6 to 5. how many women are their if their are 3600 men?

1 answer:

umka2103 [35]2 years ago

4 0

Answer:

3,000

Step-by-step explanation:

6:5

1.2( divided 6 by 5):1 (Divide 5 by 5)

3600 divided by 1.2

3,000

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Step-by-step explanation:

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Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

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$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

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2 years ago

How do I do this please help

Umnica [9.8K]

Answer:

wrong as his calculation was incorrect at initial level itself when he found the result of the division

Step-by-step explanation:

Andre said

3 ÷ $\frac{2}{3}$

$=3 \times \frac{3}{2}$

$=\frac{3 \times 3}{2}$

$=\frac{9}{2}$

but andre calculated it as

$=4\tfrac{1}{3}$

$=\frac{4 \times 3 + 1}{3}$

$=\frac{13}{3}$

Hence his calculation was incorrect at initial level itself

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3 years ago