Answer:
To find cosθ, use the formula for the area of a triangle i.e. AREA=1/2 x a x b x sinC.=> For this case: 15= 1/2 x 10 x 5 x sinC to find sinC.=> SinC = 3/5 thus, Arcsin(3/5)=+- 4/5 or +-0.8
To find the exact length of BC, use the cosine rule.=> c(sq)=a(sq)+b(sq)-2abCosC=> c(sq)=10(sq)+5(sq)-2(10)(5)(+-4/5)=> c(sq)= Square root of 205
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The point-slope form the line which has the value of slope -5 and contains a point as A(2,-1) is (y+1)=-5(x-2).
<h3>What is point slope form?</h3>
The point slope form of a line is the expression of line which has a specified slope and passes through a point.
The point slope form is givne as,
(y-y₁)=m(x-x₁)
Here, m is the slope of the line, x₁ is the x coordinate of the point by which line passes and y₁ is the y coordinate of the same point.
The slope of a line is -5. This line contains the point A (2,-1). Thus, the point slope form is,
(y-y₁)=m(x-x₁)
(y-(-1))=-5(x-2)
(y+1)=-5(x-2)
Thus, the point-slope form the line which has the value of slope -5 and contains a point as A(2,-1) is (y+1)=-5(x-2).
Learn more about the point slope form here;
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Answer:
The answer to this question is A >
Step-by-step explanation:
I got it right on edge 2020 :)
Answer:
<h2>
b = -2</h2>
Step-by-step explanation:
The point-slope form of equation is: y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope.
m = 2
(4, 6) ⇒ x₀ = 4, y₀ = 6
So, the point-slope form of equation:
y - 6 = 2(x - 4)
Changing to the slope-intercept form of the equation of the line (y = mx + b, where m is the slope and b is the y-intercept of the line):
y - 6 = 2x - 8 {add 6 to both sides}
y = 2x - 2 ⇒ b = -2
