Answer:9
Step-by-step explanation:pp
You subtract 11 from 19 and then the answer is 8
Answer:
The answer to your question is speed = 81.5 mi/h
Step-by-step explanation:
Data
distance = 230 ft
time = 1.932 s
speed = ? mi/h
Process
1.- Convert the distance to mi
1 mile ----------------- 5280 ft
x ----------------- 230 ft
x = (230 x 1) / 5280
x = 0.044 mi
2.- Convert time to hours
1 h ------------------ 3600 s
x ------------------ 1.932 s
x = (1.932 x 1) / 3600
x = 0.00054 h
3.- Calculate the speed
speed = distance / time
-Substitution
speed = 0.044/ 0.00054
-Result
speed = 81.5 mi/h
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.
So x = pi/2, pi/2 + pi = 3pi/2.
3/4 2/3
This is a multiplication of fractions
1.- Multiply the numerators and the denominators
3/4 x 2/3 = (3x 2) / (4 x 3)
= 6/12
2.- Simplify
= 3/6
= 1/2
